如何找到两个元组列表之间的差异

Question

I have two lists, which are the output of my previous codes:

List_1 = [((1.1, 2, 3), (1.1, 2, 3, 4), (3, 4, 5), 5, 6, 7)]
List_2 = [((1.1, 2, 3), (1.1, 2, 3, 4), (3, 4.4, 5), 5, 6, 7)]

I know these two lists only have one element, and I am trying to remove the parentheses and make them like:

List_1 = [(1.1, 2, 3), (1.1, 2, 3, 4), (3, 4, 5), 5, 6, 7]
List_2 = [(1.1, 2, 3), (1.1, 2, 3, 4), (3, 4.4, 5), 5, 6, 7]

What I want is to compare each element from two lists and output the elements of the second list which differ from those of the first list, like this:

Error = (3, 4.4, 5)

Does anyone know how to compare it? Thank you in advance.

Answer 1

you can use basic for loop and if statement to check values:

List_1 = [((1.1, 2, 3), (1.1, 2, 3, 4), (3, 4, 5), 5, 6, 7)]
List_2 = [((1.1, 2, 3), (1.1, 2, 3, 4), (3, 4.4, 5), 5, 6, 7)]

List_1 = list(List_1[0]) # [(1.1, 2, 3), (1.1, 2, 3, 4), (3, 4, 5), 5, 6, 7]
List_2 = list(List_2[0]) # [(1.1, 2, 3), (1.1, 2, 3, 4), (3, 4.4, 5), 5, 6, 7]

for i in range(len(List_1)):
    if List_1[i] != List_2[i]:
        print ("Error: {}".format(List_2[i]))

output:

Error: (3, 4.4, 5)