具有多种类型的通用方法

Question

If I want a generic method to have many generic types, eg up to 16.

Do I have to overload the method 16 times or is there any smarter way to do this?

public interface IMyInterface { }

public class MyClass {
    public void MyMethod<T1>() where T1 : IMyInterface { }
    public void MyMethod<T1, T2>() where T1 : IMyInterface where T2 : IMyInterface { }
    public void MyMethod<T1, T2, T3>() where T1 : IMyInterface where T2 : IMyInterface 
                                       where T3 : IMyInterface { }
    public void MyMethod<T1, T2, T3, T4>() where T1 : IMyInterface where T2 : IMyInterface 
                                           where T3 : IMyInterface where T4 : IMyInterface { }
    // All the way to T16...
    // Is there any smarter way of doing this
    // instead of having to write it 16 times?
}

Answer 1

if you look at the documentation of Action<T1, T2, ....> it seems that you need to implement all overloads singlehandedly.

Here is the reference source of it. As you see it is done as in your example.

A more detailed answer as to why a params equivalent does not exist can be found by Jon Skeet here . It states:

"Fundamentally Func<T> and Func<T1, T2> are entirely unrelated types as far as the CLR is concerned, and there's nothing like params to specify multiple type arguments."