[英]Creating array of struct dynamically in golang
I try to create a generic function that accepts any struct value and create a array of that struct type.我尝试创建一个通用函数,该函数接受任何结构值并创建该结构类型的数组。 Here is the code I tried.
这是我试过的代码。 But I get the error "t is not a type".
但我收到错误“t 不是类型”。 How can I implement this.
我该如何实现这一点。
type RegAppDB struct {
nm string
data []interface{}
}
func CreateRegTable(tbl string, rec interface{}) RegAppDB {
t := reflect.TypeOf(rec)
fmt.Println(t)
return RegAppDB{"log", []t}
}
Go does not support generics, and any attempt to do something like that is not going to work out well. Go 不支持泛型,任何类似的尝试都不会奏效。 In your specific case, there are a couple of key problems:
在您的具体情况下,有几个关键问题:
reflect.TypeOf
) happens too late to use the way you're trying to do it. reflect.TypeOf
)都太晚了,无法使用您尝试使用的方式。[]interface{}
, which means the only type you can use for that field is []interface{}
.[]interface{}
类型,这意味着您可以用于该字段的唯一类型是[]interface{}
。 []string
, for example, is a different type, and cannot be assigned to that field.[]string
是一种不同的类型,不能分配给该字段。I took another route.我走了另一条路。 Need some beautification.
需要一些美化。 But this works.
但这有效。 So now data is an array of interface and from calling function I pass pointer to structure variables to Save function.
所以现在数据是一个接口数组,从调用函数我将指向结构变量的指针传递给 Save 函数。
type RegAppDB struct {
nm string
data []interface{}
cnt int
}
// CreateRegTable creates a data structure to hold the regression result
func CreateRegTable(tbl string) *RegAppDB {
return &RegAppDB{tbl, make([]interface{}, 20), 0}
}
// Save implements saving a record Regression application DB
func (rga *RegAppDB) Save(rec interface{}) error {
rga.data[rga.cnt] = rec
rga.cnt++
return nil
}
// Show implements showing the regression table
func (rga *RegAppDB) Show() error {
fmt.Println(rga.cnt)
for i := 0; i <= rga.cnt; i++ {
fmt.Println(rga.data[i])
}
return nil
}
// Compare compares two regression table for equality
func (rga *RegAppDB) Compare(rgt *RegAppDB) bool {
return reflect.DeepEqual(rga, rgt)
}
It cannot be done for a generic type.它不能用于泛型类型。 If there are a fixed number of possible types, then you can do something like the following:
如果有固定数量的可能类型,那么您可以执行以下操作:
type RegAppDB struct {
nm string
data interface{}
}
func CreateRegTable(rec interface{}) RegAppDB {
switch rec.(type) {
case int:
return &RegAppDB{"log", []int{}}
case string:
return &RegAppDB{"log", []string{}}
}
return nil
}
Note: Your data
in RegAppDB
should be of type interface{}
since []int
implements interface{}
but not []interface{}
注意:您在
RegAppDB
data
应该是interface{}
类型,因为[]int
实现了interface{}
而不是[]interface{}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.