对AZ，0-9和-使用正则表达式和-？

Question

I have a long method like this, that has hard coded each character. Is there a way to use Regex for something like this, to make it much shorter , and much easier ?

private static bool IsValid(char character)
{
    return new List<char>(new[]
    {
        'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l',
        'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x',
        'y', 'z', '1', '2', '3', '4', '5', '6', '7', '8', '9', '0', '-', '.'
    }).Contains(character);
}

Answer 1

I suggest to check ranges , eg

private static bool IsValid(char character) {
  return character >= 'a' && character <= 'z' || // letters
         character >= '0' && character <= '9' || // digits
         character == '-' ||                     // special characters
         character == '.';
}

Techically, you can use regular expressions but it is an overshoot :

private static bool IsValid(char character) {
  return Regex.IsMatch(character.ToString(), @"[a-z0-9\.\-]");
}