正则表达式：仅限AZ字符

Question

Hi guys I have a string for example...

"Afds 1.2 45002"

What I wanted to do using regex is to start from the left, return characters AZ || az until an unmatached is encountered.

So in the example above I wanted to return "Afds".

Another example

"BCAD 2.11 45099 GHJ"

In this case I just want "BCAD".

Thanks

Answer 1

您想要的表达式是： /^([A-Za-z]+)/

Answer 2

use this regular expression (?i)^[az]+

Match match = Regex.Match(stringInput, @"(?i)^[a-z]+");

(?i) - ignore case

^ - begin of string

[az] - any latin letter

[az ] - any latin letter or space

+ - 1 or more previos symbol

Answer 3

string sInput = "Afds 1.2 45002";

Match match = Regex.Match(sInput, @"^[A-Za-z]+",
              RegexOptions.None);

// Here we check the Match instance.
if (match.Success)
{
    // Finally, we get the Group value and display it.
    string key = match.Groups[1].Value;
    Console.WriteLine(key);
}