正则表达式匹配数字和它们之间最多一个空格

Question

I am trying to match phone numbers in the following patterns:

9 99 99 99 99
0999999999
11 0999999999
9 9999 9999

But not the following:

9 99  99 99 99 (two spaces)
9 99\n99 99 99 

Therefore, I want to match 7 to 12 digits and an optional spaces between them, but not sequences of more than one white space.

So far I came up with "[\\d ?]{7,12}" , but it doesn't really match the requirements as the spaces are counted in the {7,12} and it also matches two sequences of spaces.

Answer 1

[\\d ?]{7,12} is a pattern that matches 7 to 12 digit, space or ? chars. It can match a ??????? string because ? is not a quantifier, but a mere question mark symbol when declared inside a character class.

If you change it to (?:\\d ?){7,12} , you may partially solve the problem, the space at the end. I suggest using

\b\d(?: ?\d){6,11}\b

See the regex demo

The word boundaries \\b will make sure you only match whole words.

Details

• \\b - leading word boundary
• \\d - a digit
• (?: ?\\d){6,11} - 6 to 11 consecutive sequences of
  • ? - an optional space
  • \\d - a single digit
• \\b - trailing word boundary.

Answer 2

I'd try

(?:\d+ ?){7,12}

The original regex was matching a character group of a space OR a digit seven to twelve times. The supplied regex matches a digit followed by a possible space seven to twelve times. That way the spaces aren't counted as part of the total.

Answer 3

you can use

\d(\s?\d){6,11}

the first \\d matches on the first digit. Next can follow a group of 6 to 11 (to make a total of 7 to 12) pairs of an optional space, followed by a digit. Multiple spaces are not allowed, as you see each optional space has digits to both sides. It can be checked here That regexp is equivalent, but shorter, to this one:

\d\s?\d\s?\d\s?\d\s?\d\s?\d((((((\s?\d)?\s?\d)?\s?\d)?\s?\d)?\s?\d)?\s?\d)?

that can be checked here .

NOTE

See that the \\s matches a newline, so you can get multiline number (as shown in the examples) If you don't like that behaviour, then narrow the space class using a simple space, as in

\d( ?\d){6,11}

that can be tested here Look, that now, a more than 12 digits number is truncated to only the first twelve, if this is not desired, use word boundary at the end, as in

\d( ?\d){6,11}\b

See it here .