[英]Retry for-loop in Python
Here is my Code for Example : 这是我的代码示例:
from time import sleep
for i in range(0,20):
print(i)
if i == 5:
sleep(2)
print('SomeThing Failed ....')
Output is : 输出为:
1
2
3
4
5
SomeThing Failed ....
6
7
8
9
But i want when Failed appear , it Retry it again and continue , like this : 但是我希望出现“失败”时,再次重试并继续,如下所示:
1
2
3
4
5
SomeThing Failed ....
5
6
7
8
9
Just put the working
part into a function, and it will retry once by checking the return value 只需将
working
部件放入函数中,它将通过检查返回值重试一次
from time import sleep
def working(i):
print(i)
if i == 5:
return False
return True
for i in range(0,10):
ret = working(i)
if ret is not True:
sleep(2)
print('SomeThing Failed ....')
working(i)
output 输出
0
1
2
3
4
5
SomeThing Failed ....
5
6
7
8
9
You could do this with a while
loop inside the for
loop, and only break out of that loop when the thing you attempted succeeded: 您可以在
for
循环内使用while
循环来执行此操作,并且仅在尝试执行的操作成功时才退出该循环:
for i in range(20):
while True:
result = do_stuff() # function should return a success state!
if result:
break # do_stuff() said all is good, leave loop
Depends a little on the task, eg you might want try-except
instead: 取决于任务,例如您可能需要
try-except
:
for i in range(20):
while True:
try:
do_stuff() # raises exception
except StuffError:
continue
break # no exception was raised, leave loop
If you want to impose a limit on the number of attempts, you could nest another for
loop like this: 如果要限制尝试次数,则可以嵌套另一个
for
循环,如下所示:
for i in range(20):
for j in range(3): # only retry a maximum of 3 times
try:
do_stuff()
except StuffError:
continue
break
from time import sleep
# Usually you check `i` only once
# which means `countdown` defaults to 1
def check(i, countdown = 1):
print(i)
# If `i` is 5 (or any other arbitrary problematic strange number)
if i == 5:
sleep(2)
# Decide if the program should try it again
# if `countdown` is 0,
# we stop retrying and continue
if countdown > 0:
print('Something Failed ...')
return check(i, countdown - 1)
# main
for i in range(0, 20):
check(i)
It retries only one time for each iteration 每次迭代仅重试一次
from time import sleep
i = 0
retry = True
while(i<20):
print(i)
if i == 5 and retry:
retry = False
sleep(2)
print('SomeThing Failed ....')
else:
i+=1
retry = True
The output is: 0 1 2 3 4 5 SomeThing Failed .... 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 输出为:0 1 2 3 4 5 SomeThing Failed .... 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19
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