在Python中重試for循環

Question

這是我的代碼示例：

from time import sleep
for i in range(0,20):
    print(i)
    if i == 5:
        sleep(2)
        print('SomeThing Failed ....')

輸出為：

1
2
3
4
5
SomeThing Failed ....
6
7
8
9

但是我希望出現“失敗”時，再次重試並繼續，如下所示：

1
2
3
4
5
SomeThing Failed ....
5
6
7
8
9

Answer 1

只需將working部件放入函數中，它將通過檢查返回值重試一次

from time import sleep

def working(i):
    print(i)
    if i == 5:
        return False
    return True

for i in range(0,10):
    ret = working(i)
    if ret is not True:
        sleep(2)
        print('SomeThing Failed ....')
        working(i)

輸出

0
1
2
3
4
5
SomeThing Failed ....
5
6
7
8
9

Answer 2

您可以在for循環內使用while循環來執行此操作，並且僅在嘗試執行的操作成功時才​​退出該循環：

for i in range(20):
    while True:
        result = do_stuff()  # function should return a success state! 
        if result:
             break  # do_stuff() said all is good, leave loop

取決於任務，例如您可能需要try-except ：

for i in range(20):
    while True:
        try:
            do_stuff()  # raises exception
        except StuffError:
            continue
        break  # no exception was raised, leave loop

如果要限制嘗試次數，則可以嵌套另一個for循環，如下所示：

for i in range(20):
    for j in range(3):  # only retry a maximum of 3 times
        try:
            do_stuff()
        except StuffError:
            continue
        break

Answer 3

from time import sleep

# Usually you check `i` only once
# which means `countdown` defaults to 1
def check(i, countdown = 1):

    print(i)

    # If `i` is 5 (or any other arbitrary problematic strange number)
    if i == 5:
        sleep(2)

        # Decide if the program should try it again
        # if `countdown` is 0,
        # we stop retrying and continue
        if countdown > 0:
            print('Something Failed ...')

            return check(i, countdown - 1)

# main
for i in range(0, 20):
    check(i)

Answer 4

每次迭代僅重試一次

from time import sleep
i = 0
retry = True
while(i<20):
    print(i)
    if i == 5 and retry:
        retry = False
        sleep(2)
        print('SomeThing Failed ....')
    else:
        i+=1
        retry = True

輸出為：0 1 2 3 4 5 SomeThing Failed .... 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19