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pygame中的敌人

[英]Enemies in pygame

Hey i'm making this space shooter game in pygame and want to spawn 10 enemies at a time. 嘿,我正在pygame中制作这个太空射击游戏,想一次生成10个敌人。 Here is the code i used: 这是我使用的代码:

    blocks.append([random.randrange(0, display_width),0])


    for block in blocks:
        pygame.draw.rect(game_display, green, (block[0],block[1], 30, 40))


    for leng in range(len(blocks)):
        blocks[leng][1]+=10


        for block in blocks:
            if block[1]<0:
                blocks.remove(block)

Using this code, my screen gets filled with enemies(green rects). 使用此代码,我的屏幕上充满了敌人(绿色矩形)。 Is there any way i can spawn a certain number of enemies at a time and keep spawning more if the enemy goes off the screen or dies? 如果敌人离开屏幕或死亡,我有什么办法可以一次产生一定数量的敌人,并继续产生更多的敌人?

Instead of a List that represent your enemies, start using the Rect class (in fact, you should use the Sprite class, but one step at a time). 开始使用Rect类而不是代表敌人的列表(实际上,您应该使用Sprite类,但一次只能使用一个步骤)。

So instead of 所以代替

blocks.append([random.randrange(0, display_width),0])


for block in blocks:
    pygame.draw.rect(game_display, green, (block[0],block[1], 30, 40))

we can write 我们可以写

blocks.append(pygame.Rect(random.randrange(0, display_width), 0, 30, 40))

for block in blocks:
    pygame.draw.rect(game_display, green, block)

and instead of 而不是

for leng in range(len(blocks)):
    blocks[leng][1]+=10


    for block in blocks:
        if block[1]<0:
            blocks.remove(block)

we can use (see how much clearer the code becomes): 我们可以使用(查看代码变得更加清晰):

for block in blocks[:]:
    block.move_ip(0, 10)
    if not game_display.get_rect().contains(block):
        blocks.remove(block)
        blocks.append(pygame.Rect(random.randrange(0, display_width), 0, 30, 40))

which will also add a new enemy whenever one leaves the screen. 每当有人离开屏幕时,它也会添加一个新敌人。 We could also just reset its position, like this: 我们也可以像这样重置它的位置:

for block in blocks:
    block.move_ip(0, 10)
    if not game_display.get_rect().contains(block):
        block.x = random.randrange(0, display_width)

So, whenever you want a new rect to appear, just call 因此,每当您要显示新矩形时,只需致电

blocks.append(pygame.Rect(random.randrange(0, display_width), 0, 30, 40))

which you may want to put into a function, or better use the Sprite class instead 您可能希望将其放入函数中,或者更好地使用Sprite

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