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C中的冒泡排序

[英]Bubble-sort in C

I am trying to program the Bubble sort sorting algorithm in C for practice and revision, however, I have come across a few issues: I am trying to print every swap after every iteration in the array of 20 random numbers, however, the program seems to get rid of items which are bigger than the item before for some reason. 我正在尝试用C编写Bubble排序排序算法以进行练习和修订,但是,我遇到了一些问题:我试图在20个随机数数组的每次迭代后打印每次交换,但是该程序似乎出于某种原因摆脱比以前更大的物品。

Here is the code: 这是代码:

int i, j, temp;
int SortData[20]= {20, 43, 90, 17, 2, 4, 67, 54, 0, 44, 78, 89, 21, 45, 72, 
88, 65, 100, 97, 25};
for(i=0; i<20; i++)
{
    printf("|%d", SortData[i]);
}
printf("|");
printf("\n");

 for (i=0; i<19; i++)
    {
        for(j=0;j<18;j++){
        if(SortData[j]>SortData[j+1])
        {
            temp = SortData[j];
            SortData[j]=SortData[j+1];
            SortData[j+1]=temp;
            printf("|%d", SortData[j]);
        }

    }
    printf("\n");
    }
    printf("\n");
system("pause");
return 0;

And here is what happens when this code is ran: 运行此代码后,将发生以下情况:

|20|43|90|17|2|4|67|54|0|44|78|89|21|45|72|88|65|100|97|25|
|17|2|4|67|54|0|44|78|89|21|45|72|88|65|97
|17|2|4|54|0|44|21|45|72|88|65
|17|2|4|0|44|21|45|72|65
|2|4|0|21|45|65
|0|21|45|65
|0|21|65
|0|21
|0

Process returned 10 (0xA)   execution time : 3.072 s
Press any key to continue.

Moreover, I ran a few tests to check whether there was a bug in the sorting of the array or in the printing of it, here are the results from that test: 此外,我运行了一些测试来检查数组排序或打印过程中是否存在错误,这是该测试的结果:

int i, j, temp;
int SortData[20]= {20, 43, 90, 17, 2, 4, 67, 54, 0, 44, 78, 89, 21, 45, 72, 
88, 65, 100, 97, 25};
for(i=0; i<20; i++)
{
    printf("|%d", SortData[i]);
}
printf("|");
printf("\n");

 for (i=0; i<19; i++)
    {
        for(j=0;j<18;j++){
        if(SortData[j]>SortData[j+1])
        {
            temp = SortData[j];
            SortData[j]=SortData[j+1];
            SortData[j+1]=temp;

        }

    }
    }
    for (i=0; i<20; i++){
        printf("|%d", SortData[i]);//Error here as 25 isn't sorted
    }
    printf("|");
    printf("\n");
system("pause");
return 0;

The only change in this snippet from the above one is that the printing statement comes out of the nested for loop and printed using a separate for loop, this kind of works, as the numbers are sorted, but fro some reason 25 isn't: 与上面的代码相比,此代码段的唯一变化是,打印语句从嵌套的for循环中出来,并使用单独的for循环进行打印,这种工作方式是对数字进行排序,但由于某些原因25不是:

|20|43|90|17|2|4|67|54|0|44|78|89|21|45|72|88|65|100|97|25|
|0|2|4|17|20|21|43|44|45|54|65|67|72|78|88|89|90|97|100|25|
Press any key to continue . . .

So it turns out that there is an issue with the sorting and the printing. 因此,事实证明排序和打印存在问题。 Could I please have some hints as to how print every iteration of the swap and get it to swap correctly? 我能否对如何打印交换的每个迭代并使其正确交换有一些提示?

UPDATE: 更新:

So I have incremented the loop counters by in the nested for loop and now it sorts out the array and shows every iteration. 因此,我在嵌套的for循环中将循环计数器增加了,现在它对数组进行排序并显示每次迭代。 Here is what the changed code looks like: 更改后的代码如下所示:

int i, j, temp;
int SortData[20]= {20, 43, 90, 17, 2, 4, 67, 54, 0, 44, 78, 89, 21, 45, 72, 88, 65, 100, 97, 25};
for(i=0; i<20; i++)
{
    printf("|%d", SortData[i]);
}
printf("|");
printf("\n");

 for (i=0; i<20; i++)
    {
        for(j=0;j<19;j++){
        if(SortData[j]>SortData[j+1])
        {
            temp = SortData[j];
            SortData[j]=SortData[j+1];
            SortData[j+1]=temp;

        }
            printf("|%d", SortData[j]);//Changed code
    }
        printf("\n");
    }
    //for (i=0; i<20; i++){
      //  printf("|%d", SortData[i]);//Error here as 25 isn't sorted
    //}
    printf("|");
    printf("\n");
system("pause");
return 0;

Now it does show every iteration, and sorts it, but for some reason the number 100 disappears from the array and thus it only sorts 19 items rather than 20: 现在它确实显示了每个迭代并对其进行排序,但是由于某种原因,数字100从数组中消失了,因此它仅对19个项目进行排序,而不是20:

|20|43|90|17|2|4|67|54|0|44|78|89|21|45|72|88|65|100|97|25|
|20|43|17|2|4|67|54|0|44|78|89|21|45|72|88|65|90|97|25
|20|17|2|4|43|54|0|44|67|78|21|45|72|88|65|89|90|25|97
|17|2|4|20|43|0|44|54|67|21|45|72|78|65|88|89|25|90|97
|2|4|17|20|0|43|44|54|21|45|67|72|65|78|88|25|89|90|97
|2|4|17|0|20|43|44|21|45|54|67|65|72|78|25|88|89|90|97
|2|4|0|17|20|43|21|44|45|54|65|67|72|25|78|88|89|90|97
|2|0|4|17|20|21|43|44|45|54|65|67|25|72|78|88|89|90|97
|0|2|4|17|20|21|43|44|45|54|65|25|67|72|78|88|89|90|97
|0|2|4|17|20|21|43|44|45|54|25|65|67|72|78|88|89|90|97
|0|2|4|17|20|21|43|44|45|25|54|65|67|72|78|88|89|90|97
|0|2|4|17|20|21|43|44|25|45|54|65|67|72|78|88|89|90|97
|0|2|4|17|20|21|43|25|44|45|54|65|67|72|78|88|89|90|97
|0|2|4|17|20|21|25|43|44|45|54|65|67|72|78|88|89|90|97
|0|2|4|17|20|21|25|43|44|45|54|65|67|72|78|88|89|90|97
|0|2|4|17|20|21|25|43|44|45|54|65|67|72|78|88|89|90|97
|0|2|4|17|20|21|25|43|44|45|54|65|67|72|78|88|89|90|97
|0|2|4|17|20|21|25|43|44|45|54|65|67|72|78|88|89|90|97
|0|2|4|17|20|21|25|43|44|45|54|65|67|72|78|88|89|90|97
|0|2|4|17|20|21|25|43|44|45|54|65|67|72|78|88|89|90|97
|0|2|4|17|20|21|25|43|44|45|54|65|67|72|78|88|89|90|97
|

Press any key to continue . . .

Why does 100 disappear? 为什么100消失了?

This works perfectly, you did a little error: 完美运行,您犯了一个小错误:

int i, j, temp;
int SortData[20]= {20, 43, 90, 17, 2, 4, 67, 54, 0, 44, 78, 89, 21, 45, 72, 88, 65, 100, 97, 25};
for(i=0; i<20; i++)
{
    printf("|%d", SortData[i]);
}
printf("|");
printf("\n");
//before for(i=0; i<19; i++)
for (i=0; i<20; i++)// i < 20 or it will skip the last number
{
    //before for(j=0; j<18; j++)
    for(j=0;j<19;j++){
        if(SortData[j]>SortData[j+1])
        {
        temp = SortData[j];
        SortData[j]=SortData[j+1];
        SortData[j+1]=temp;
        }

    }
}
for (i=0; i<20; i++){
    printf("|%d", SortData[i]);
}
printf("|");
printf("\n");
return 0;

If you want to print every iteration of the bubble sorting, this is the code: 如果要打印气泡排序的每个迭代,请使用以下代码:

int i, j, temp, h;
int SortData[20]= {20, 43, 90, 17, 2, 4, 67, 54, 0, 44, 78, 89, 21, 45, 72, 88, 65, 100, 97, 25};
for(i=0; i<20; i++)
{
    printf("|%d", SortData[i]);
}
printf("|");
printf("\n");

for (i=0; i<20; i++)
{
    for(j=0;j<19;j++){
        if(SortData[j]>SortData[j+1])
        {
            temp = SortData[j];
            SortData[j]=SortData[j+1];
            SortData[j+1]=temp;
            for (h=0; h<20; h++)
            {
                printf("|%d", SortData[h]);
            }
            printf("|");
            printf("\n");
        }
    }
}
return 0;
}

on line 11 of that code snippet you put in, you're only using the first 19 records for sorting. 在您输入的代码段的第11行中,您仅使用前19条记录进行排序。 Set this code to 20 and solve. 将此代码设置为20并求解。

I comment the line where i fix. 我评论我修复的那一行。

Tip: Possibly you are starting out in software development and for this type of case it would be interesting to learn how to use a debug. 提示:可能您是刚开始软件开发,对于这种情况,学习如何使用调试会很有趣。

int i, j, temp;
int SortData[20]= {20, 43, 90, 17, 2, 4, 67, 54, 0, 44, 78, 89, 21, 45, 72, 
88, 65, 100, 97, 25};
for(i=0; i<20; i++)
{
    printf("|%d", SortData[i]);
}
printf("|");
printf("\n");

// before > for (i=0; i<19; i++)
 for (i=0; i<20; i++)
    {
// before > for(j=0;j<18;j++){
    for(j=0;j<19;j++){
        if(SortData[j]>SortData[j+1])
        {
            temp = SortData[j];
            SortData[j]=SortData[j+1];
            SortData[j+1]=temp;

        }

    }
    }
    for (i=0; i<20; i++){
        printf("|%d", SortData[i]);//Error here as 25 isn't sorted
    }
    printf("|");
    printf("\n");
system("pause");
return 0;

You're just skipping the last number , when you are using for loop. 使用for循环时,您只是跳过最后一个数字。 Run your for loop for i<20 instead of i<19 because it is skipping the last number while sorting. 为i <20而不是i <19运行for循环,因为它在排序时跳过了最后一个数字。

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