检查一列是否与另一列的列表中的所有对象匹配

Question

I have a dataframe with one column of strings and another with a list of strings.

                     0                     1
0      apples are good      [orange, banana]
1     bananas are good        [bananas, bad]
2  cucumbers are green      [cucumbers, are]
3     grapes are green  [grapes, are, green]
4     oranges are good             [oranges]
5   pineapples are big     [flowers, apples]

I want the find all the indices where the string in Column 0 matches all the list contents in Column 1 . In this case the output would look like:

                     0                     1
2  cucumbers are green      [cucumbers, are]
3     grapes are green  [grapes, are, green]
4     oranges are good             [oranges]

I know I can use pandas.Series.str.contains but that only works on a single list and I want to avoid iterating/looping if possible.

Answer 1

You can use a list comprehension and Boolean indexing:

res = df[[all(word in x.split() for word in y) for x, y in zip(df[0], df[1])]]

print(res)

                     0                     1
2  cucumbers are green      [cucumbers, are]
3     grapes are green  [grapes, are, green]
4     oranges are good             [oranges]