[英]I want to generate random numbers within given range in java
For that, I got the solution but I can't understand it: I have used below function to generate random numbers within the given range but what is the meaning of below function? 为此,我得到了解决方案,但我不明白:我使用了below函数来生成给定范围内的随机数,但是below函数的含义是什么?
static int randomRangeInNumber(int min, int max) {
Random r=new Random();
return r.nextInt((max-min)+1)+min;
}
What i have returned i didnt get Please help making me understand its meaning any help will be appreciated 我没有得到的退货请帮助我理解其含义,将不胜感激
The documentation for nextInt(int bound) says nextInt(int bound)的文档说
Returns a pseudorandom, uniformly distributed int value between 0 (inclusive) and the specified value (exclusive), drawn from this random number generator's sequence. 返回一个伪随机数,它从此随机数生成器的序列中提取,在0(含)和指定值(不含)之间均匀分布的int值。
So your nextInt
call is 所以你的nextInt
电话是
(max-min)+1
) and then 取返回值,范围为[0..bound](界限为(max-min)+1
),然后 +min
. 用+min
将其缩放到[min..max]范围。 return r.nextInt((max-min)+1)+min;
\__________1_________/\_2_/
nextInt is normally exclusive of the top value, so add 1 to make it inclusive nextInt通常不包含最高值,因此加1使其包含在内
So, in your case, we'll say the max
is 10 and min
is 5. 因此,在您的情况下,我们说max
为10, min
为5。
nextInt(n)
will give you a random number between 0 and n - 1. nextInt(n)
将为您提供0到n-1之间的随机数。
So adding the +1
will let you include the value of n
. 因此,加上+1
将使您包括n
的值。
nextInt(max-min)
therefore gives you a random number between (in this case) 0 and 5 - 1 (and include the 5 because of the +1) nextInt(max-min)
为您提供一个在0和nextInt(max-min)
之间的随机数(在这种情况下,由于+1而包括了5)
Then adding the min
again, means it will give you the above random number, but add 5 to it, so the result will be a random number between 5 and 10. 然后再次加上min
,表示它将为您提供上述随机数,但将其加5,因此结果将是5到10之间的随机数。
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