TypeScript：任何实现特定接口的类

Question

Let's say I have this interface

interface CanFly {
  fly(): void;
}

And I will create two classes, Bird and AirPlane that both implement the above interface.

And finally, I want to create a function that is flyIn2Seconds , which looks like this:

function flyIn2Seconds(who: any extends CanFly) {
  setTimeout(() => who.fly(), 2000);
}

However any extends CanFly doesn't work ( [ts] '?' expected. ). Is there a way to specify the type "any class that implements CanFly"?

Answer 1

You simply specify the interface:

function flyIn2Seconds(who: CanFly) {
  setTimeout(() => who.fly(), 2000);
}

More in the interfaces documentation .