接口字段应具有实现该接口的类的类型-typescript

Question

I am wondering if this is achievable in Typescript.

interface Pine {

    child : <The class that implements this interface>
}

class Vine implements Pine {

    child : Vine // this is enforced to be Vine, rather than any object that implements Pine.
}

I know from this question that you cannot do it in Java, but what about TS? I have looked up tslang doc without fruition.

Answer 1

You can use Generics. eg :

interface Base<T> {
    child: T;
}

class Derived implements Base<string> {
    child: string;
} 

class Derived2 implements Base<number> {
    child: number;
}