计算shell脚本中由find函数找到的文件，并将它们保存在数组中

Question

I would like to make a shell script that finds a specific file and then asks the user which file he wants. But when I for example use the find command

(find . -name 2D.py)

it finds two files:

 ./Desktop/2D.py ./libcpab-master/2D.py 

save these into a file:

file=$(find . -name 2D.py)

and counts them:

echo "${#key[@]}"

I get that only one name. It should be 2 files. Also when I save 'file' in a array, there is only one element.

Hope you can help.

Answer 1

You have to define the "file" variable as an array. Try this

> find . -name 2D.py
./Desktop/2D.py
./libcpab-master/2D.py
> set -A file
> file=$(find . -name 2D.py)
> echo "${file[*]}"
./Desktop/2D.py
./libcpab-master/2D.py
> echo "${file[*]}" > file_list
> cat file_list
./Desktop/2D.py
./libcpab-master/2D.py
> wc file_list
 2  2 39 file_list
>