[英]Extract bits into a int slice from byte slice
I have following byte slice which from which i need to extract bits and place them in a []int as i intend to fetch individual bit values later. 我有以下字节切片,我需要从中提取位并将它们放在[] int中,因为我打算稍后获取单个位值。 I am having a hard time figuring out how to do that. 我很难搞清楚如何做到这一点。
below is my code 下面是我的代码
data := []byte{3 255}//binary representation is for 3 and 255 is 00000011 11111111
what i need is a slice of bits -- > [0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1]
我需要的是一块位 - > [0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1]
What i tried 我尝试了什么
strconv.FormatUint
but that fails with error panic: runtime error: index out of range
我尝试使用BigEndian将字节切片转换为Uint16,然后尝试使用strconv.FormatUint
但失败并出现错误panic: runtime error: index out of range
fmt.Printf
function but that is not useful for me as i need a int slice for further bit value access. 看到许多使用fmt.Printf
函数的简单输出位表示数字的例子,但这对我来说fmt.Printf
,因为我需要一个int slice来进行进一步的位值访问。 Do i need to use bit shift operators here ? 我需要在这里使用位移操作符吗? Any help will be greatly appreciated. 任何帮助将不胜感激。
One way is to loop over the bytes, and use a 2nd loop to shift the byte values bit-by-bit and test for the bits with a bitmask. 一种方法是循环遍历字节,并使用第二个循环逐位移位字节值并使用位掩码测试位。 And add the result to the output slice. 并将结果添加到输出切片。
Here's an implementation of it: 这是它的一个实现:
func bits(bs []byte) []int {
r := make([]int, len(bs)*8)
for i, b := range bs {
for j := 0; j < 8; j++ {
r[i*8+j] = int(b >> uint(7-j) & 0x01)
}
}
return r
}
Testing it: 测试它:
fmt.Println(bits([]byte{3, 255}))
Output (try it on the Go Playground ): 输出(在Go Playground上试试):
[0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1]
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