I have following byte slice which from which i need to extract bits and place them in a []int as i intend to fetch individual bit values later. I am having a hard time figuring out how to do that.
below is my code
data := []byte{3 255}//binary representation is for 3 and 255 is 00000011 11111111
what i need is a slice of bits -- > [0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1]
What i tried
strconv.FormatUint
but that fails with error panic: runtime error: index out of range
fmt.Printf
function but that is not useful for me as i need a int slice for further bit value access. Do i need to use bit shift operators here ? Any help will be greatly appreciated.
One way is to loop over the bytes, and use a 2nd loop to shift the byte values bit-by-bit and test for the bits with a bitmask. And add the result to the output slice.
Here's an implementation of it:
func bits(bs []byte) []int {
r := make([]int, len(bs)*8)
for i, b := range bs {
for j := 0; j < 8; j++ {
r[i*8+j] = int(b >> uint(7-j) & 0x01)
}
}
return r
}
Testing it:
fmt.Println(bits([]byte{3, 255}))
Output (try it on the Go Playground ):
[0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1]
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