[英]MySQL Find records in one table that has no value of a column in another table
I have table1, containing columns (simplified): 我有table1,其中包含列(简体):
+-------------------------+
| id | user_id | username |
+----+---------+----------+
| 1 | 123 | peter |
| 2 | 234 | john |
+-------------------------+
and table 2, containing columns (simplified): 和表2,其中包含列(简体):
+----------------------------------+
| id | user_id | checklist_item_id |
+----+---------+-------------------+
| 1 | 123 | 110 |
| 2 | 123 | 111 |
| 3 | 123 | 112 |
| 4 | 234 | 110 |
| 5 | 234 | 112 |
+----------------------------------+
As shown above, Each entry for user_id from table1, has multiple entries for that user_id with multiple checklist_item_ids. 如上所示,表1中user_id的每个条目都有该user_id的多个条目以及多个checklist_item_ids。
I am interested in returning ONLY records that does NOT have an entry in the second table for checklist_item_id = 111. The query must return only: 我有兴趣返回仅第二张表中没有checklist_item_id = 111条目的记录。查询必须仅返回:
+---------+
| user_id |
+---------+
| 234 |
+---------+
As user with user_id 123 DO have an entry in table two with checklist_item_id of 111. 作为具有user_id 123的用户,请在表2中具有一个checklist_item_id为111的条目。
You can use subquery, for example: 您可以使用子查询,例如:
SELECT *
FROM table1
WHERE user_id NOT IN
(SELECT user_id
FROM table2
WHERE checklist_item_id = 111)
use corelated subquery 使用相关子查询
select t1.* from table1 t1 where t1.user_id not in
( select user_id from table2 t2
where t2.user_id=t1.user_id
and checklist_item_id=111
)
Or use not exist
which is efficient than not in 或使用not exist
比不使用更有效的方法
select t1.* from table1 t1 where not exists
( select 1 from table2 t2 where t2.user_id=t1.user_id and
checklist_item_id=111
)
id userid itemid
4 234 110
5 234 112
In case you need only one id then it would be 如果您只需要一个ID,那么它将是
select distinct t1.userid from t1 where not exists
( select 1 from t1 t2 where t2.userid=t1.userid and
itemid=111
)
output 输出
userid
234
Simplest and efficient approach would be using LEFT JOIN
, and filtering out those rows, where there is no matched record for checklist_item_id = 111
最简单有效的方法是使用LEFT JOIN
,并过滤掉那些没有checklist_item_id = 111
匹配记录的行。
SELECT DISTINCT t1.user_id
FROM table1 AS t1
LEFT JOIN table2 AS t2 ON t2.user_id = t1.user_id AND
t2.checklist_item_id = 111
WHERE t2.user_id IS NULL
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