如何在基于 Node.js 的应用程序和 node-mysql 驱动程序中从 MySQL 数据库中选择多条记录？

Question

I am running the below query in mysql db and i want to store the results in an array ? How can I do that in node.js ?

SELECT ProductName FROM products;

Answer 1

The last SELECT statement you have described is almost correct except that it uses structure for the INSERT statement.

Here is 2 correct ways to create and execute SELECT statements, the safe way, to avoid MySQL injections and to secure your database from possible attacks.

1. Multiple Records

    /**
     * Example of Selecting multiple rows form one MySQL table
     */

    var query = connection.query('SELECT ProductName FROM products', 
    [product_id], function(err, results) { 

         if (error) throw error; output error(s)

         // results[0]['ProductName'];
         // results[1]['ProductName'];
         // ...

    }); 

1. Using a prepared Statement targeting for specific rows:

    /** * Example of Selecting one record using MySQL Table ID */ var category_id = 5; var query = connection.query('SELECT ProductName FROM products WHERE CategoryId=?', [category_id], function(err, results) { if (error) throw error; output error(s) // results[0]['ProductName']; // results[1]['ProductName']; // ... });

2. Using mysql.escapeId() method

   var category_id = x; var sql = 'SELECT productName FROM products WHERE category_id = ' + connection.escape(category_id); connection.query(sql, function (error, results, fields) { if (error) throw error; output error(s) // results[0]['ProductName']; // results[1]['ProductName']; // ... });