如何在没有 toJS 的情况下从 immutable.js 的orderedmap 中获取所有有序值？

Question

I have such an orderedmap like this:

{
 "200": { id: 200, name: "John" },
 "120": { id: 120, name: "Mike" },
 "350": { id: 350, name: "James" }
}

How to get all ordered values ​​without toJS method?
I've tried:

map.valueSeq().toArray(), Array.from(map.values())

but it returns an intermixed array .

Answer 1

You could do toList() to get all the values (ei not the keys ) of the map in a List immutable structure you can further manipulate later, or do List(yourMap) if you want the key and value as a tuple array of sorts. Per the docs :

This is similar to List(collection), but provided to allow for chained expressions. However, when called on Map or other keyed collections, collection.toList() discards the keys and creates a list of only the values, whereas List(collection) creates a list of entry tuples.

const { Map, List } = require('immutable') var myMap = Map({ a: 'Apple', b: 'Banana' }) List(myMap) // List [ [ "a", "Apple" ], [ "b", "Banana" ] ] myMap.toList() // List [ "Apple", "Banana" ]

---

Aclaration:

Javascript will sort your source object keys if they are numeric or parseable as numeric, so you can do the following workaround:

const PeopleMap = new OrderedMap([
 ["200", { id: 200, name: "John" }],
 ["120", { id: 120, name: "Mike" }],
 ["350", { id: 350, name: "James" }]
]);

Here's a working example: https://jsfiddle.net/8kbcyfsn/

By declaring it as a key value pair array, the ordered map registers the right order.

Whereas if you declare it as an object,

const PeopleMap = new OrderedMap({
 "200": { id: 200, name: "John" },
 "120": { id: 120, name: "Mike" },
 "350", { id: 350, name: "James"}
});

It will attempt to order it by the Number(key) value.

Answer 2

我不确定我是否正确理解了您的问题，但如果我理解了，您可以尝试：

Object.keys(obj).map(key => obj[key]);