如何在shell脚本中将awk的输出获取到数组中

Question

I am comparing two files and displaying the lines which are not similar, when I just keep

echo $(awk 'FNR==NR{f[$0]+=1; next} !($0 in f)' $file1 $file2)

I am able to get the values.

When I try to do the same by passing into array , I am getting ":command not found" error

declare -a myarr=()
myarr=$("$(awk 'FNR==NR{f[$0]+=1; next} !($0 in f)' $file1 $file2 )")

Please help , thanks in advance.

Answer 1

Remove the quotes plus the leading dollar:

myarr=$("$(awk 'FNR==NR{f[$0]+=1; next} !($0 in f)' $file1 $file2 )")

should be

myarr=($(awk 'FNR==NR{f[$0]+=1; next} !($0 in f)' $file1 $file2))

Check:

• Word Splitting
• Double Quotes
• Arrays

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Btw, your awk command won't print lines which are unique to file1. Probably the comm command is what you want, but note that comm expects sorted input:

comm -13 <(sort "${file1}") <(sort "${file2}")