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如何在Spring Data JDBC中编写自定义@Query?

[英]How to write a custom @Query in Spring Data JDBC?

In Spring Data JDBC examples, how do I write a simple query in @Query annotation? 在Spring Data JDBC示例中,如何在@Query批注中编写一个简单查询?

eg In LegoSet Repository , how do I add a simple findByName query? 例如在LegoSet Repository中 ,如何添加一个简单的findByName查询?

When I tried 当我尝试

@Query("select * from lego_set where name = :name") List<LegoSet> findByName(@Param("name") String name); it throws following error: 它引发以下错误:

org.springframework.data.mapping.MappingException: Could not read property @org.springframework.data.annotation.Id() @org.springframework.data.relational.core.mapping.Column(value=handbuch_id, keyColumn=)private java.lang.Long example.springdata.jdbc.basics.aggregate.Manual.id from result set!
...

> Caused by: org.hsqldb.HsqlException: Column not found: manual_handbuch_idat org.hsqldb.error.Error.error(Unknown Source) at org.hsqldb.error.Error.error(Unknown Source) `

Also, the reference document seems to be copied from some generic spring data document since it mentioned derived query which doesn't exist in spring data jdbc yet. 另外,该参考文档似乎是从某些通用的Spring数据文档复制而来的,因为它提到了Spring数据jdbc中尚不存在的派生查询。

The LegoSet entity has a 1:1 relationship to a Manual . LegoSet实体与Manual具有1:1关系。 Spring Data JDBC selects such a construct using a join and expects the representative columns in the ResultSet . Spring Data JDBC使用联接选择这种构造,并期望ResultSet的代表列。

Note that it expects the columns representing the Manual entity itself plus the one forming the back-reference to the LegoSet . 请注意,它期望代表Manual实体本身的列以及构成对LegoSet的反向引用的LegoSet Also, all column names are to be prefixed by the property name + _ , ie manual_ in this case. 同样,所有列名都应以属性名+ _作为前缀,在这种情况下,即manual_

The error message actually tells you about the missing column (modulo a missing space): Column not found: manual_handbuch_id . 错误消息实际上告诉您有关缺少的列(以空格为模): Column not found: manual_handbuch_id

Alternatively, you can also provide your own RowMapper 另外, 您也可以提供自己的 RowMapper

Regarding the documentation: 关于文档:

You are kind of right. 你是对的。 The documentation of (almost) all Spring Data modules includes a generic part which easily leads to confusion. (几乎)所有Spring Data模块的文档都包含一个通用部分,很容易引起混淆。 There is a ticket for comming up with a better solution . 一个更好的解决方案的门票

I think you are trying to execute a native query.So,try as below 我认为您正在尝试执行本机查询。因此,请尝试以下操作

@Query(  value = "SELECT * FROM lego_set ls where ls.name = :name",
           nativeQuery = true)
  List<LegoSet> findByName(@Param("name") String name);

This should work. 这应该工作。

Just as a completion of @jens-schauder's answer: 就像@ jens-schauder的答案一样:

The query should be: 查询应为:

    @Query("SELECT ls.id, ls.name, ls.min_age, ls.max_age, " +
            "h.handbuch_id AS manual_handbuch_id, h.author AS manual_author, h.text AS manual_text " +
            "FROM lego_set ls JOIN handbuch h ON ls.id = h.handbuch_id " +
            "WHERE name = :name")
    List<LegoSet> findByName(@Param("name") String name);

Using this method the following test passes: 使用此方法,以下测试通过:

    @Test
    public void so_52978700() {
        // prepare
        LegoSet cars = createLegoSet("Small Car - 01", 5, 10);
        cars.setManual(new Manual("Just put all the pieces together in the right order", "Jens Schauder"));
        repository.save(cars);

        // execute
        List<LegoSet> actual = repository.findByName("Small Car - 01");

        // verify
        assertThat(actual).hasSize(1);
        assertThat(actual.get(0).getName()).isEqualTo("Small Car - 01");
        assertThat(actual.get(0).getManual().getText()).isEqualTo("Just put all the pieces together in the right order");
    }

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