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如何使用 LIKE 针对具有 Spring 数据的列编写查询?

[英]How do I write a query with LIKE against a column with Spring Data?

I have a PSQL table with a text column and a query我有一个带有文本列和查询的 PSQL 表

select * from table where :number: like column||'%';

where :number: is a parameter.其中:number:是一个参数。

How can I write that query in Spring Data JPA?如何在 Spring 数据 JPA 中编写该查询? The LIKE stuff of Spring Data seems to take only a text parameter, not a column name. Spring Data 的 LIKE 东西似乎只采用文本参数,而不是列名。

This is possible using JPA Criteria Queries or Specifications .这可以使用JPA Criteria Queries or Specifications来实现。 Both use Path#get(String attributeName) to create a path corresponding to the referenced column name.两者都使用Path#get(String attributeName)创建与引用的列名对应的路径。 I assume you have an entity named Table .我假设您有一个名为Table的实体。

Example with Criteria Queries:标准查询示例:

public List<Table> getCoulmnLikeNumber(String columnName, String number) {
    CriteriaBuilder builder = getEntityManager().getCriteriaBuilder();
    CriteriaQuery<Table> critQuery = builder.createQuery(Table.class);
    Root<Table> root = critQuery.from(Table.class);

    Expression<String> pattern = builder.concat(root.<String>get(columnName), "%");
    critQuery.select(root)
             .where(builder.like(builder.literal(number), pattern));

    return getEntityManager()
            .createQuery(critQuery)
            .getResultList();
}

A factory method for your specification could look similar to this:您的规范的工厂方法可能类似于以下内容:

public static Specification<Table> columnNameLikeNumber(String columnName, String number) {
    return new Specification<Table>() {
        @Override
        public Predicate toPredicate(Root<Entity> root,
                                     CriteriaQuery<?> query, CriteriaBuilder builder) {
            Expression<String> pattern = builder.concat(root.<String>get(columnName), "%");
            return builder.like(builder.literal(number), pattern);
        }
    };
}

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