[英]comparison counter on binary search
So, I have a binary search code (not mine) and I don't know how to put a counter on how many comparisons it made.所以,我有一个二进制搜索代码(不是我的),但我不知道如何将计数器放在它进行了多少次比较上。 The elements are entered then sorted.
输入元素然后排序。 Then this codes comes after.
然后这个代码来了。
System.out.println("\nEnter value to find");
num_search = in.nextInt();
first = 0;
last = n - 1;
middle = (first + last)/2;
while( first <= last )
{
if ( a[middle] < num_search )
first = middle + 1;
else if ( a[middle] == num_search )
{
System.out.println(num_search + " found at location " + (middle + 1) + ".");
System.out.println("Counter = " + (ctr + middle));
break;
}
else
last = middle - 1;
middle = (first + last)/2;
}
if (first > last)
System.out.println(num_search + " isn't present in the list.\n");
You can increment count like this:您可以像这样增加计数:
int count = 0;
while( first <= last )
{
if ( a[middle] < num_search ) {
count+= 1;
first = middle + 1;
}
else if ( a[middle] == num_search )
{
count+= 2;
System.out.println(num_search + " found at location " + (middle + 1) + ".");
break;
}
else {
count+= 3;
last = middle - 1;
}
middle = (first + last)/2;
}
System.out.println("Counter = " + count);
Simply increment the value of ctr
for all the three cases.只需为所有三种情况增加
ctr
的值。 Make sure you have initialized the ctr
with 0
;确保您已使用
0
初始化ctr
;
while( first <= last )
{
if ( a[middle] < num_search )
{first = middle + 1;
ctr++; //<----increment the count by 1
}
else if ( a[middle] == num_search )
{
ctr++; //<----increment the count by 1
System.out.println(num_search + " found at location " + (middle + 1) + ".");
System.out.println("Counter = " + ctr); //<-----add 1 to result
break;
}
else
{last = middle - 1;
ctr++; //<----increment the count by 1
}
middle = (first + last)/2;
}
if (first > last)
System.out.println(num_search + " isn't present in the list.\n");
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