在第N个字符出现时分割字符串

Question

I have this a lot of strings like this:

29/10/2018 14:50:09402325 671

I want to split these string so they are like this:

29/10/2018 14:50

09402325 671

These will then be added to a data set and analysed later.

The issue I am having is if I use this code:

 string[] words = emaildata.Split(':');

it splits them twice; I only want to split it once on the second occurrence of the :.

How can I do that?

Answer 1

You can use LastIndexOf() and some subsequent Substring() calls:

string input = "29/10/2018 14:50:09402325 671";

int index = input.LastIndexOf(':');

string firstPart = input.Substring(0, index);
string secondPart = input.Substring(index + 1);

Fiddle here

However, another thing to ask yourself is if you even need to make it more complicated than it needs to be. It looks like this data will always be of a the same length until that second : instance right? Why not just split at a known index (ie not finding the : first):

string firstPart = input.Substring(0, 16);
string secondPart = input.Substring(17);

Answer 2

您可以反转字符串，然后调用常规的split方法询问单个结果，然后反转两个结果

Answer 3

and with a regex : https://dotnetfiddle.net/Nfiwmv

using System;
using System.Text.RegularExpressions;

public class Program  {
    public static void Main() {
        string input = "29/10/2018 14:50:09402325 671";
        Regex rx = new Regex(@"(.*):([^:]+)",
            RegexOptions.Compiled | RegexOptions.IgnoreCase);

        MatchCollection matches = rx.Matches(input);
        if ( matches.Count >= 1 ) {
            var m = matches[0].Groups;
            Console.WriteLine(m[1]);
            Console.WriteLine(m[2]);        
        }
    }
}