[英]Complex numbers calculator
So, if I type (4*9j**2) into the console, it returns (-324+0j) Is there any way to re-create this with code, basically, take input and simplify it as if you just typed it into the console (j acts as the imaginary number i) 因此,如果我在控制台中键入(4 * 9j ** 2),它将返回(-324 + 0j)是否有任何方法可以使用代码重新创建此代码,基本上,请像输入它一样进行输入并简化它进入控制台(j代表虚数i)
Thanks in advance! 提前致谢!
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