在C ++中逼近零方向的最佳方法

Question

I have some troubles explaining clearly but it's rather simple..

I have a double named value in my C++ program and I want to Floor it if it's a positive value and Ceil if it's a negative value, the precision is given by an external variable.

An example:

precision is of 1000 value is 0.2659 so approximated value is 0.265
value is -0.2659 so approximated value is -0.265

I have wrote a simple code but I was wondering if there was a more simple or/and way to do it.

Here what I have so far:

void NodeImpl::approximation(double& value, const double& precision)
{
    if (value > 0.0)
    {
        value = std::floor(value * precision);
    }
    else
    {
        value = std::ceil(value * precision);
    }
    value /= precision;
}

I have wrote a simple code but I was wondering if there was a more simple or/and way to do it.

Answer 1

你可以使用std::trunc ：

return std::trunc(value * precision) / precision;