如何使用while循环从列表中的每个整数中减去最小的数字？

Question

input:

5
30
50
10
70
65

5 is how many numbers follow after.

My code:

n = int(input())
list = []
i = 0
while len(list) < n:
    integer = int(input())
    list.append(integer)
    i = i + 1
    minList = min(list)
    integers = list[i - 1] - minList
    print(integers)

I'm suppose to subtract the smallest number from the 5 integers.

The correct output: 20 40 0 60 55

My output: 0 20 0 60 55

I understand why my output is wrong since the smallest number is 20 until 10 is inputed, but I don't know how to correct it. I tried different ways, but none of them work. How do I subtract the smallest number from each integer?

Answer 1

Get the inputs to a list. Take minimum of this list using min() and then subtract minimum value from each of the list elements:

n = int(input())                  # Read number of numbers
lst = []

for _ in range(n):
    lst.append(int(input()))      # Append to list

min_value = min(lst)              # Take the minimum number
final_lst = [abs(x-min_value) for x in lst]  # Subtract minimum from each number

Answer 2

Collect all the input first, then find the minimum value and print the numbers.

n = int(input())
numbers = []
while len(numbers) < n:
    integer = int(input())
    numbers.append(integer)
smallest = min(numbers)
for number in numbers:
    print number - smallest

Answer 3

size = int(input())
lst = [int(input()) for _ in range(size)]
m = min(lst)
res = [abs(n - m) for n in lst]

Answer 4

This looks like a default puzzle for sites like Hackerrank ... take all the inputs , then perform your operations on all inputs. Do not meddle with data while still gathering inputs (unless it makes sense to do so).

A nice way of getting all the data is:

n = int(input())    # get how many inputs follow

# get n inputs, perform the int() conversion, store as list.
data = list(map(int, (input().strip() for _ in range(n))))

# calculate the min value
min_value = min(data)

# print all reduced values in order each on one line
print( *[x-min_value for x in data], sep = "\n")
# or comma seperated:
print( *[x-min_value for x in data], sep = ",")

Output:

# print with sep="\n"
20
40
0
60
55

# print with sep=","
20,40,0,60,55

Read the doku for map() , int() , min() and look at Built in functions : do not use those as names for your variables, neither use list , dict , set , tuple .

Answer 5

Try this:

l = list()
for _ in range(int(input())):
    l.append(int(input()))
xmin = min(l)
print(*[x - xmin for x in l])

Output:

C:\Users\Documents>py test.py
5
30
50
10
70
65
20 40 0 60 55