查看字符串中字母“y”之前是否有元音

Question

x = input()
vowels = ['a', 'e', 'i', 'o', 'u']

I am trying to use an if statement that shows if y is in the string (without knowing the position of the y in the string).

If there are any vowels before y , print(1) ; if not print (2) , and if there is no y in the word print(3) .

Answer 1

import re

word = "wordy"
ypos = word.find("y")

if ypos != -1:
    if(bool(re.search(('|'.join(["a","e","i","o","u"])),word[:ypos]))):
        print("1")
    else:
        print("2")
else :
    print("3")

Answer 2

>>> def y_in_word(word):
...     if 'y' not in word:
...             print 3
...     elif any([x in word for x in ['ay', 'ey', 'iy', 'oy', 'uy']]):
...             print 2
...     else:
...             print 1
...
>>>
>>> y_in_word('wordy')
1
>>> y_in_word('worday')
2
>>> y_in_word('worda')
3
>>>

Answer 3

Without using regex:

x = input()
vowels = "aeiou"

for i in range(len(x)):
    if x[i] == "y":
        break

if x[i] != "y":  # No y found
    print(3)
else:
    flag = 0
    new_str = x[:i+1]
    for ch in new_str:
        if ch in vowels:
            print(1)
            flag += 1
            break

    if flag == 0:
        print(2)

Answer 4

x = input()
vowels = ['a', 'e', 'i', 'o', 'u']

if 'y' in x:
    # find the position of 'y' in the input string
    y_position = x.index(y)

    # loop through each vowel
    for vowel in vowels:
        # if the vowel is in the input string and its position is before y
        if vowel in x and x.index(vowel) < y_position:
            print(1)
            break

    # if we made it all the way through the loop without breaking, we did not find
    # any vowels before y
    else:
        print(2)

else:
    print(3)

Answer 5

First become lowercase and then judge

import re
x = input().lower()
m = re.findall("(?=a|e|i|o|u)\w*?(?=y)",x)
if "y" in x.lower():
    if m:
        print(1)
    else:
        print(2)
else:
    print(3)