Python在每个元音之前添加字符串

Question

I am writing a python code that takes a single imputed line of text and adds the string "tak" before every vowel (y only counting as a vowel if it doesn't begin a word) for example "I like sleep" would come out to "takI ltakitake sltaketakep". I am only just beginning learning to code and as such do not know too many complex functions yet. Below is the code I have thus far, which isn't working at all.

text = raw_input("enter the text to be translated")
textSplit = text.split()
count = 0
print len(textSplit)
Vowels = ["a","e","i","o","u"]
while count <= len(text):
  for i in textSplit:
    for i in Vowels:
      count += 1

However, I have not been able to figure out how I can slice the string, add "tak" and concatenate it. Thank you.

edit: can it be done without using the text.replace module?

Answer 1

You can use a regex :

>>> re.sub(r'(?i)([aeiou])', r'tak\1', "I like sleep") 
'takI ltakiktake sltaketakep'

You can also use str.replace by looping over the string once for each vowel. Don't forget that strings are immutable in Python so you have to create a new string each time:

>>> s="I like sleep"
>>> for v in 'aeiouAEIOU':
...    s=s.replace(v, 'tak'+v)
... 
>>> s
'takI ltakiktake sltaketakep'

In this case, the string s is either the same as before if the vowel is not found or each vowel is replaced by the string tak concatenated to the vowel. A new string is created in either case each time through the loop and assigned to s .

Answer 2

If you need to ignore any leading 'y's, you'll have to finesse it just a bit:

text = raw_input("enter the text to be translated")

temp1 = temp2 = text[1:] if text[0] in ['y', 'Y'] else text

for vowel in ['a', 'e', 'i', 'o', 'u', 'y']:
    temp2 = temp2.replace(vowel, 'tak{}'.format(vowel))
    temp2 = temp2.replace(vowel.upper(), 'tak{}'.format(vowel.upper()))

text = text.replace(temp1, temp2)
print text

For an input of 'I like sleep', this gives:

takI ltakiktake sltaketakep

'yellow':

ytakelltakow

'turkey':

ttakurktaketaky

If, for some reason, you really didn't want to use str.replace , you could do it like this:

text = raw_input("enter the text to be translated")

temp2 = text[1:] if text[0] in ['y', 'Y'] else text
vowels = ['a', 'e', 'i', 'o', 'u', 'y']

temp2 = ''.join(['tak{}'.format(letter) if letter.lower() in vowels else letter for letter in temp2])

if text[0] in ['y', 'Y']:
    text = text[0] + temp2
else:
    text = temp2

print text

Answer 3

You could use re.sub :

re.sub(r'([aeiou])', r'(exampleReplace)\1', text)

Example:

text = 'Text'
print(re.sub(r'([aeiou])', r'(exampleReplace)\1', text))
>> T(exampleReplace)ext

Answer 4

The following would work:

text = 'I like sleep'
vowels = set("aeiou")
modified_text = ''.join(['tak'+letter if letter.lower() in vowels else letter for letter in text])
print(modified_text)

Output

takI ltakiktake sltaketakep

(note: I think you are missing a k in your sample output)

Answer 5

Use list() instead of split() . I have also used enumerate to get the index and value simultaneously. Modified code:

text = "I like banana"
textSplit = list(text)
Vowels = ["a","e","i","o","u"]
for index,letter in enumerate(textSplit):
    if letter.lower() in Vowels:
        textSplit[index] = "tak" + letter
print "".join(textSplit)

Output:

takI ltakiktake btakantakantaka