（Java数字金字塔）如何使我的数字在它们之间具有更多的空格，同时当它是大于9的整数时准确对齐吗？

Question

I am having difficulty getting the desired output. I know there are problems that are similar to mine that is already posted, but I find it hard to relate my code to their solutions without a massive overhaul.

The solution for my class assignment:

Supposed to continue until every direction of pyramid equals 1 My second method "spaces" is redundant and I am not sure why. Any help would be appreciated.

Blockq

    public static void main(String[] args) {
        numPar();
        spaces();
    }

    private static void spaces() {
        int x = 0;
        if(x > 0 && x < 10) {
            System.out.print("   "); 
        } else if (x > 10 && x < 99) {
            System.out.print("  ");  
        } else if (x > 99) {
            System.out.print(" ");  
        }
    }

    private static void numPar() {
        int spaces = 14;
        for(int i = 0; i<= 7; i++) {
            for(int u = 0; u<spaces; u++) {
                System.out.print(" ");
            }
            spaces--;
            spaces--;
            for(int j = 0 ; j <i ; j++) {
                System.out.print(""+ (int) Math.pow(2,j)+" ");
            }
            for(int k = i ; k >=0 ; k--) {
                System.out.print(""+ (int) Math.pow(2,k)+" ");
            }
            System.out.println("");
        }
    }
}

Answer 1

I made every number take 3 places using String.format("%3s", (int) Math.pow(2, j)) . You can make it dynamic by replacing the number 3 here with the length of the largest number you'll print. I also changed the number of spaces in your print statements. Here is the full code that prints an evenly spaced pyramid:-

public static void main(String[] args) {
    numPar();
    spaces();
}

private static void spaces() {
    int x = 0;
    if (x > 0 && x < 10) {
        System.out.print("   ");
    } else if (x > 10 && x < 99) {
        System.out.print("   ");
    } else if (x > 99) {
        System.out.print("   ");
    }
}

private static void numPar() {
    int spaces = 14;
    for (int i = 0; i <= 7; i++) {
        for (int u = 0; u < spaces; u++) {
            System.out.print("  ");
        }
        spaces--;
        spaces--;
        for (int j = 0; j < i; j++) {
            System.out.print("" + String.format("%3s", (int) Math.pow(2, j)) + " ");
        }
        for (int k = i; k >= 0; k--) {
            System.out.print("" + String.format("%3s", (int) Math.pow(2, k)) + " ");
        }
        System.out.println("");
    }
}

String.format explanation :-
String.format("%3s", str) will print the string str , padding it with spaces, to make the total length 3 if it's less than 3. Note that you can write anything instead of 3 - I used 3 because your biggest number was of length 3.

So "A" will be printed as "_ _ A" (2 spaces), and "Ab" will be printed as "_ Ab" (1 space).

I just replaced str with your Math.pow(2, j) .