带有响应array []的jQuery Ajax PHP POST方法instad发送了数据。 如何获得发送值作为响应？

Question

I am creating simple application which will insert log data into database table.

Going with jQuery Ajax POST method and JSON format for data.

My index.php has HTML and this code:

<script type="text/javascript">
jQuery(document).ready(function() {
    jQuery.ajax({
        type: "POST",
        url: "http://www.example.com/ajax_model.php",
        data: {
            "log_session": "27738d7552b75ae395ae1138adf4fa60",
            "log_ip": "1.2.3.4",
            "log_vrijeme": "2018-11-23 01:22:47",
            "log_model": "12345"
        },
        dataType: "json",
        contentType: 'application/json; charset=utf-8',
        success: function(response) {
            console.log(response);
            alert(response);
        },
        error: function(error) {
            console.log(error);
        }
    });
});
</script>

My ajax_model.php - which gives me response Array[] instad the data which is sent:

<?php
if(isset($_POST)){
    header('Content-Type: application/json');
    echo json_encode($_POST);
    exit;
}
?>

I am getting result in my console.log() and alert() - Array[] . How can I output my sent response to check if the data was correctly sent over Ajax?

Am I missing some brackets like [] or {} ? Or do I need to add something to my ajax_model.php file?

Thank you for suggestion and provided information.

Answer 1

You aren't sending JSON so get rid of:

 contentType: 'application/json; charset=utf-8',

That will cause $_POST to be empty as the default contentType is:

application/x-www-form-urlencoded; charset=UTF-8