使用awk行到列

Question

I would like to know how I could transform the following ('Old') to 'New1' and 'New2' using awk:

Old:

5
21
31
4
5
11
12
15
5
19
5
12
5
.
.

New1:

5 21 31 4
5 11 12 15
5 19
5 12
. 
.

New2:

521314
5111215
519
512
. 
.

Thanks so much!

Answer 1

Requires gawk for multi-character RS :

$ awk 'BEGIN {RS="\n5\n"} {$1=$1; print (NR>1 ? 5 OFS $0 : $0)}' file
5 21 31 4
5 11 12 15
5 19
5 12   

For the second version, just set OFS to the empty string:

$ awk -v OFS="" 'BEGIN {RS="\n5\n"} {$1=$1; print (NR>1 ? 5 OFS $0 : $0)}' file
521314
5111215
519
512

Answer 2

To get new1 :

awk '/^5/{printf "%s", (NR>1?RS:"")$0;next}{printf " %s",$0}END{print ""}' file

To get new2 :

awk '/^5/{printf "%s", (NR>1?RS:"")$0;next}{printf "%s",$0}END{print ""}' file

Answer 3

some variation of @jas's script

$ awk -v RS="(^|\n)5\n" -v OFS='' 'NR>1{$1=$1; print 5,$0}' file
521314
5111215
519
512

$ awk -v RS="(^|\n)5\n" -v OFS=' ' 'NR>1{$1=$1; print 5,$0}' file
5 21 31 4
5 11 12 15
5 19
5 12

in the second one you don't have to set the OFS explicitly since it's the default value, otherwise both scripts are the same (essentially same as the other referenced answer).

Answer 4

With any awk:

$ awk -v ORS= '{print ($0==5 ? ors : OFS) $0; ors=RS} END{print ors}' file
5 21 31 4
5 11 12 15
5 19
5 12

$ awk -v ORS= -v OFS= '{print ($0==5 ? ors : OFS) $0; ors=RS} END{print ors}' file
521314
5111215
519
512