使用char []属性创建对象的实例

Question

I have a class with an char[] property, but when I try to create an instance of it I get an error. My code is this:

Class:

public class Board
{
    private char[] priFC;

    public Board(char[] priFC){
        this.priFC = priFC;
    }
...}

Main:

Board Tab = new Board(char[10]);

I get an invalid expression term char at the creation of Tab

Answer 1

In Main, while creating instance of Tablero pass instance of char[] , instead of char[10] something like

Tablero Tab = new Tablero(new []{'s','t','a','c','k','o','v','e','r','f','l','o','w'});

or

Tablero Tab = new Tablero(new char[10]);

or

char [] charInstance = new char[]{'s','t','a','c','k','o','v','e','r','f','l','o','w'};
Tablero Tab = new Tablero(charInstance);