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如何将整数的pytorch张量转换为布尔值的张量?

[英]How to convert a pytorch tensor of ints to a tensor of booleans?

I would like to cast a tensor of ints to a tensor of booleans.我想将整数张量转换为布尔值张量。

Specifically I would like to be able to have a function which transforms tensor([0,10,0,16]) to tensor([0,1,0,1])具体来说,我希望能够有一个函数将tensor([0,10,0,16])tensor([0,1,0,1])

This is trivial in Tensorflow by just using tf.cast(x,tf.bool) .这在 Tensorflow 中只需使用tf.cast(x,tf.bool)

I want the cast to change all ints greater than 0 to a 1 and all ints equal to 0 to a 0. This is the equivalent of !!我希望强制转换将所有大于 0 的整数更改为 1,将所有等于 0 的整数更改为 0。这相当于!! in most languages.在大多数语言中。

Since pytorch does not seem to have a dedicated boolean type to cast to, what is the best approach here?由于 pytorch 似乎没有专用的布尔类型可以转换,这里最好的方法是什么?

Edit: I am looking for a vectorized solution opposed to looping through each element.编辑:我正在寻找一个矢量化的解决方案,而不是遍历每个元素。

What you're looking for is to generate a boolean mask for the given integer tensor.您正在寻找的是为给定的整数张量生成一个布尔掩码 For this, you can simply check for the condition: "whether the values in the tensor are greater than 0" using simple comparison operator ( > ) or usingtorch.gt() , which would then give us the desired result.为此,您可以简单地检查条件:“张量中的值是否大于 0”,使用简单的比较运算符 ( > ) 或使用torch.gt() ,然后会给我们所需的结果。

# input tensor
In [76]: t   
Out[76]: tensor([ 0, 10,  0, 16])

# generate the needed boolean mask
In [78]: t > 0      
Out[78]: tensor([0, 1, 0, 1], dtype=torch.uint8)

# sanity check
In [93]: mask = t > 0      

In [94]: mask.type()      
Out[94]: 'torch.ByteTensor'

Note : In PyTorch version 1.4+, the above operation would return 'torch.BoolTensor'注意:在 PyTorch 1.4+ 版本中,上述操作将返回'torch.BoolTensor'

In [9]: t > 0  
Out[9]: tensor([False,  True, False,  True])

# alternatively, use `torch.gt()` API
In [11]: torch.gt(t, 0)
Out[11]: tensor([False,  True, False,  True])

If you indeed want single bits (either 0 s or 1 s), cast it using:如果您确实想要单个位( 0秒或1秒),请使用以下方法进行转换:

In [14]: (t > 0).type(torch.uint8)   
Out[14]: tensor([0, 1, 0, 1], dtype=torch.uint8)

# alternatively, use `torch.gt()` API
In [15]: torch.gt(t, 0).int()
Out[15]: tensor([0, 1, 0, 1], dtype=torch.int32)

The reason for this change has been discussed in this feature-request issue: issues/4764 - Introduce torch.BoolTensor ...此功能请求问题中已讨论了此更改的原因: issues/4764 - Introduce torch.BoolTensor ...


TL;DR : Simple one liner TL;DR : 简单的一个衬垫

t.bool().int()

You can use comparisons as shown below:您可以使用如下所示的比较:

 >>> a = tensor([0,10,0,16])
 >>> result = (a == 0)
 >>> result
 tensor([ True, False,  True, False])

Convert boolean to number value:将布尔值转换为数值:

 a = torch.tensor([0,4,0,0,5,0.12,0.34,0,0]) print(a.gt(0)) # output in boolean dtype # output: tensor([False, True, False, False, True, True, True, False, False]) print(a.gt(0).to(torch.float32)) # output in float32 dtype # output: tensor([0., 1., 0., 0., 1., 1., 1., 0., 0.])

Another option would be to simply do:另一种选择是简单地做:

temp = torch.tensor([0,10,0,16])
temp.bool()
#Returns
tensor([False,  True, False,  True])

PyTorch's to(dtype) method has convenient data-type named aliases . PyTorch 的to(dtype) dtype to(dtype)方法具有方便的名为 aliases 的数据类型 You can simply call bool :您可以简单地调用bool

>>> t.bool()
tensor([False,  True, False,  True])
>>> t.bool().int()
tensor([0, 1, 0, 1], dtype=torch.int32)

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