SQL：从表中选择行，其中列的每个元素都是矩阵？

Question

I have a huge table with several columns. Each element in column_H is a little matrix 2x4, with booleans.

I need to SELECT the rows WHERE the 8 boolean elements in column_H, per row, are False.

Is it possible? How? (I am employing a Python wrapper to SQL)

Answer 1

Well, if your database supports booleans, then you would just do:

select t.*
from t
where not bool1 and not bool2 and not bool3 and not bool4 and
      not bool5 and not bool6 and not bool7 and not bool8;

If your values are bit-encoded, then they are not "boolean"s. It might work to compare:

where column_h = 0

Answer 2

Each element in col_H is a matrix, so I don't have direct access to each boolean but only to the matrix.

Since I am employing a Python wrapper to SQL, I just figured I could try to mix both languages :-S

And now I managed to make it work! My actual code is:

select *
from table 
where    col_H[0,0] == False 
      && col_H[0,1] == False 
      && col_H[1,0] == False 
      && col_H[1,1] == False 
      && col_H[2,0] == False 
      && col_H[2,1] == False 
      && col_H[3,0] == False 
      && col_H[3,1] == False 
;

It works perfectly.

Thanks!