Pandas - get_dummies 与选定的集合

Question

With the following DataFrame:

>>> df = pd.DataFrame(data={'category':['a','b','c'],'val':[1,2,3]})
>>> df
  category  val
0        a    1
1        b    2
2        c    3

I'm concatenating the produced dummy columns and droping the original column like so:

>>> df = pd.concat([df, pd.get_dummies(df['category'], prefix='cat')], axis=1).drop(['category'], axis=1)
>>> df
   val  cat_a  cat_b  cat_c
0    1      1      0      0
1    2      0      1      0
2    3      0      0      1

I'm then adding another column for a future unknown value, like so:

>>> df['cat_unkown'] = 0
>>> df
   val  cat_a  cat_b  cat_c  cat_unkown
0    1      1      0      0           0
1    2      0      1      0           0
2    3      0      0      1           0

---

Now I would like to get_dummies on a new DataFrame, but map it to the available columns, meaning: If a category column exists, use it otherwise set the cat_unkown to 1

for example for the following DataFrame:

  category  val
0        a    1
1        b    2
2        d    3

The result would be:

   val  cat_a  cat_b  cat_c  cat_unkonw
0    1      1      0      0           0
1    2      0      1      0           0
2    3      0      0      0           1

What would be an efficient way to do it?

Update : Just elaborating a bit, In my real-world problem, I have the data frames after the get_dummies produced the results.

Answer 1

I believe you need:

df = pd.DataFrame(data={'category':['a','b','c'],'val':[1,2,3]})  
df = pd.concat([df, pd.get_dummies(df['category'], prefix='cat')], axis=1).drop(['category'], axis=1)  
df['cat_unkown'] = 0
print (df)
   val  cat_a  cat_b  cat_c  cat_unkown
0    1      1      0      0           0
1    2      0      1      0           0
2    3      0      0      1           0

df1 = pd.DataFrame(data={'category':['a','b','d'],'val':[1,2,3]})    
df1 = pd.concat([df1, pd.get_dummies(df1['category'], prefix='cat')], axis=1).drop(['category'], axis=1)  
print (df1)
   val  cat_a  cat_b  cat_d
0    1      1      0      0
1    2      0      1      0
2    3      0      0      1

---

#get all columns names without val
orig_cols = df.columns.difference(['val'])
print (orig_cols)
Index(['cat_a', 'cat_b', 'cat_c', 'cat_unkown'], dtype='object')

 #create dictionary with all columns from df1 which are not in df (also removed vals column)
dif = dict.fromkeys(df1.columns.difference(['val'] + orig_cols.tolist()), 'cat_unkown')
print (dif)
{'cat_d': 'cat_unkown'}

#rename columns and if-else for possible multiplied renamed columns
df3 = (df1.rename(columns=dif)
        .assign(cat_unkown = lambda x: x.pop('cat_unkown').max(axis=1) 
                             if isinstance(x['cat_unkown'], pd.DataFrame) 
                             else x.pop('cat_unkown'))
        .reindex(columns=orig_cols, fill_value=0)
        )

print (df3)
   cat_a  cat_b  cat_c  cat_unkown
0      1      0      0           0
1      0      1      0           0
2      0      0      0           1