Python如何查找列表中是否有数字，而不是列表的最后一个数字？

Question

I have a list of numbers and want to know if a number is in the list but is not the last number in the list. Maybe something like this?

for i in all_guesses:
        if guess == i:
            if guess != all_guesses[-1]:
            #Code here

Answer 1

use in to test form membership and slicing to exclude the last number:

print(guess in my_list[:-1])

EDIT: OP is not clear as to what is desired output incase there are repeating elements in the list, in particular if the last elements is repeated/present elsewhere in the list. In this case you need to check that it's not equal to last element.

print(guess in my_list[:-1] and guess != my_list[-1])

Answer 2

If guess in all_guesses and all_guesses.index(guess)! = len(all_guesses):
    print "Present but not last" 

The only problem is, it won't work if you have duplicate elements in the list and one is at the end of the list. as index returns the index of first occurance.

Answer 3

l1 = [1,2,3]
l2 = [1,2,3,4]
n = 3

print( (n in l1 and n != l1[-1]) )
print( (n in l2 and n != l2[-1]) )

results in

False
True

Answer 4

Slice the last element off your list.

>>> my_list = [3, 1, 4, 6]
>>> without_last = my_list[:-1]
>>> without_last
[3, 1, 4]
>>> 
>>> guess = 6
>>> guess in my_list
True
>>> guess in without_last
False

If you have to do this queck often (and if your list contains more than a few elements) consider constructing a set for the constant-time membership test with

without_last = set(my_list[:-1])

Answer 5

Slice the list with [:-1] and check the number with in

listOfValues = [1, 2, 3, 4]
number = 1
if number in listOfValues[:-1]:
    print(number)