如何找到给定数字与 Python 列表中每个元素之间的最小差异？

Question

Say I have:

[1, 2, 3, 4]

and the integer

6

I want to compare 6 with every element in the list and return the element with the smallest absolute value difference which in this case is 4 . Is there an efficient Numpy way to do it?

Answer 1

You can use argmin on the absolute difference to extract the index, which can then be used to extract the element:

a = np.array([1, 2, 3, 4])

a[np.abs(a - 6).argmin()]
# 4