在C中将指针分配给结构的问题

Question

This is the error that I get in my program:

[Error] cannot convert 'struct(*)[5] ' to 'struct* {aka Contact*}' in assignment

When I try to do this:

typedef struct Contact{
    char FName[];
    char LName[];
} cont;                                                                    

cont AddressBook[SIZE];                                                   

int main(){ 
    cont *adbook = (cont *)calloc (SIZE, sizeof(cont));
    adbook=&AddressBook
}

How can I assing the address of my array of structs to my pointer???

Hope you can help me.

Answer 1

When we declare arrays, It's variable name is actually already a pointer pointing it's address.

So when you're performing

adbook=&AddressBook;

It is like saying point to the address of the pointer which points to AddressBook. This is Invalid assignment. (Somewhat like assigning Pointer to Pointer (**) to a single Pointer(*)).

This can be solved easily by removing the '&' operator while assigning to the pointer. Making it :

adbook=AddressBook;

That would simply mean "Point to the location of AdressBook.

Happy Coding !