[英]Matlab trigonometric functions
I am fairly new to Matlab. 我是Matlab的新手。 I wrote a code in C++ to calculate the length of the base of triangle in respect to alpha angle, the code works as expected. 我用C ++编写了一个代码来计算三角形底边相对于alpha角的长度,代码按预期工作。 Now I would like to complete the same task in Matlab and plot results. 现在我想在Matlab中完成相同的任务并绘制结果。
C++ code C ++代码
#include <iostream>
using namespace std;
#include <tgmath.h>
int a = 135;
int b = 125;
double base;
double alphaB;
double alphaC;
double alphaA;
float difference;
#define PI 3.14159265358979323846
int main() {
for(int i = 1; i < 90; i++){
alphaA = i * PI/180;
alphaB = asin((b*sin(alphaA))/a);
alphaC = 180*PI/180 - alphaA - alphaB;
base = (a*sin(alphaC))/(sin(alphaA));
cout << base << endl;
}
return 0;
}
Matlab script Matlab脚本
y = 0:1:90;
z = my(y);
plot(z,y)
function base = my(x)
a = 135; %Side A lenght
b = 125; %Side B lenght
f = x * pi/180;
alphaB = asin((b*sin(f))/a);
alphaC = 180*pi/180 - f - alphaB;
base = (a*sin(alphaC))/(sin(f));
disp(base);
end
when I run the Matlab script the output is just one number and the plot is empty, so I wrote another debugging script stripping "(a*sin (alpha)) /(sin (f))" equation into pieces 当我运行Matlab脚本时,输出只是一个数字而且图是空的,所以我写了另一个调试脚本,将“(a * sin(alpha))/(sin(f))”方程式分解成碎片
y = 1:1:5;
z = my(y);
plot(z,y)
function base = my(x)
a = 135; %Side A lenght
b = 125; %Side B lenght
f = x * pi/180;
alphaB = asin((b*sin(f))/a);
alphaC = 180*pi/180 - f - alphaB;
alphaC2 = sin(alphaC);
sf = sin(f);
aa = a*alphaC2;
test = aa/sf; % division problem
base = aa;
disp(test);
disp(aa);
disp(sf);
end
It turns out the problem is when it comes to division, when displaying "aa,sf" I got all of the output, 90 numbers. 事实证明问题在于划分,当显示“aa,sf”时,我得到了所有的输出,90个数字。 When the script hits "test = aa/SF" I have single output(one number). 当脚本命中“test = aa / SF”时,我有单输出(一个数字)。 How to overcome this problem? 如何克服这个问题?
You would want to use ./ instead of / 您可能希望使用./而不是/
/ is a matrix division ./ is a division of each element. /是矩阵除法./是每个元素的一个除法。
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