[英]Replace characters in string with a custom alphabet
I have written this code that replaces the characters in a string with a custom supplied alphabet: 我编写了这段代码,用自定义提供的字母替换字符串中的字符:
//Replaces characters in string with custom alphabet.
public static String getStringWithCustomAlphabet(String string, String customAlphabet){
String shiftedString = "";
//Loop through every character in @plainText
for (int i = 0; i < string.length(); i++) {
//Store current character of loop in @charToAdd
char charToAdd = string.charAt(i);
int index = getAlphabet().indexOf(charToAdd);
//If index is valid
if (index != -1) charToAdd = customAlphabet.charAt(index);
//Add the character to @cipherText
shiftedString += charToAdd;
}
return shiftedString;
}
public static String getAlphabet() {
return "abcdefghijklmnopqrstuvwxyz ";
}
This code works. 此代码有效。 However, I want to be able to use not only a String alphabet but an integer alphabet.
但是,我希望不仅可以使用字符串字母,而且可以使用整数字母。 So, for example:
因此,例如:
int[] numberArray {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26};
getStringWithCustomAlphabet("abcxyz", numberArray); //Should return 0,1,2,23,24,25
Maybe there is some way to simply this code and not use a for loop? 也许有某种方法可以简化此代码,而不使用for循环?
For lower case use this : 对于小写字母,请使用:
String str = "abcdef";
char[] ch = str.toCharArray();
for (char c : ch) {
int temp = (int) c;
int temp_integer = 96; //for lower case
if (temp <= 122 & temp >= 97)
System.out.print(temp-temp_integer);
}
Output will be -:123456
输出将是-:123456
For Upper case : 对于大写:
String str = "DEFGHI";
char[] ch = str.toCharArray();
for (char c : ch) {
int temp = (int) c;
int temp_integer = 64; //for upper case
if (temp <= 90 & temp >= 65)
System.out.print(temp-temp_integer);
}
Output Will be -:456789
输出将是-:456789
Strategy pattern may save you a lot of time and give you maximum flexibility. 策略模式可以为您节省大量时间,并为您提供最大的灵活性。 Suppose that we define an
AlphabetConverter
interface, as: 假设我们定义一个
AlphabetConverter
接口,如下所示:
@FunctionalInterface
interface AlphabetConverter {
String convert(char ch);
}
Then, define the convertAlphabet
method accepting an AlphabetConverter
, as: 然后,将接受
AlphabetConverter
的convertAlphabet
方法定义为:
public String convertAlphabet(String actual, AlphabetConverter converter) {
StringBuilder sb = new StringBuilder();
for (int i = 0; i < actual.length(); i++) {
sb.append(converter.convert(actual.charAt(i)));
}
return sb.ToString();
}
Now, you can implement AlphabetConverter
, one for replacement with String
alphabet, and one for int
array, or even use a lambda function. 现在,您可以实现
AlphabetConverter
,一个用于替换String
字母,一个用于int
数组,甚至使用lambda函数。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.