[英]es6 filter an array of objects by an array of filter objects
given the following structure: 给出以下结构:
let filteredTasks = [
{status: 'done', other: true},
{status: 'nope', other: false},
{status: 'done', other: true},
{status: 'done', other: true},
{status: 'done', other: false},
{status: 'done', other: false},
{status: 'started', other: false}
]
and: 和:
let availableFilters = [{status: 'done'}, {other: false}]
how can I filter this array to get the following results: 如何过滤此数组以获得以下结果:
filteredTasks =
[{status: 'done', other: false}, {status: 'done', other: false}]
my thoughts and attempts: 我的想法和尝试:
let filteredTasks = [
{status: 'done', other: true},
{status: 'nope', other: false},
{status: 'done', other: true},
{status: 'done', other: true},
{status: 'done', other: false},
{status: 'done', other: false},
{status: 'started', other: false}
]
let availableFilters = [{status: 'done'}, {other: false}]
let filteredTasksList = availableFilters.map(item => {
return runFilter(item)
})
function runFilter(currentFilter) {
return filteredTasks.filter(item => {
for (var key in currentFilter) {
if (item[key] === undefined || item[key] !== currentFilter[key])
return false
}
return true;
})
}
...but obviously this is overriding each pass. ......但显然这是每次通过的最重要的。
As always any feedback and help is greatly appreciated, so thanks in advance. 一如既往的任何反馈和帮助非常感谢,所以提前感谢。
EDIT: accepted the initial comment as the solution as it fits my needs. 编辑:接受最初的评论作为解决方案,因为它符合我的需要。 I used that to take it a step further:
我用它来更进一步:
let filterTaskList = (list, filters) => {
let entries = Object.entries(Object.assign(...filters))
return list.filter(task => {
return entries.every(([key, val]) => {
return task[key] === val
})
})
}
You could create a single object of the filters and take the entries for filtering. 您可以创建过滤器的单个对象并将条目用于过滤。
let filteredTasks = [ {status: 'done', other: true}, {status: 'nope', other: false}, {status: 'done', other: true}, {status: 'done', other: true}, {status: 'done', other: false}, {status: 'done', other: false}, {status: 'started', other: false} ], availableFilters = [{status: 'done'}, {other: false}], // your filters filters = Object.entries(Object.assign(...availableFilters)), // returns an array of the filter's own enumerable property result = filteredTasks.filter(o => filters.every(([k, v]) => o[k] === v)); // .every returns true, when every item is fulfilling the condition console.log(result);
Code first: 代码优先:
let filteredTasks = [ {status: 'done', other: true}, {status: 'nope', other: false}, {status: 'done', other: true}, {status: 'done', other: true}, {status: 'done', other: false}, {status: 'done', other: false}, {status: 'started', other: false} ] let availableFilters = [{status: 'done'}, {other: false}] const matchesFilter = (filter, item) => Object.entries(filter).every(([key, value]) => item[key] === value) function withFilters (filters) { return item => filters.every(f => matchesFilter(f, item)) } console.log(filteredTasks.filter(withFilters(availableFilters)))
Explanation: the two interesting functions here are matchesFilter
and withFilters
. 说明:这里有两个有趣的函数是
matchesFilter
和withFilters
。
matchesFilter
: takes an object, the filter
and compares every key/value to the item
to ensure it matches. matchesFilter
:获取一个对象, filter
并将每个键/值与item
进行比较以确保它匹配。
withFilters
takes in a list of filters and returns a function that can be used with Array.prototype.filter
to produce a filtered list. withFilters
接收过滤器列表并返回一个可与Array.prototype.filter
一起使用的函数,以生成过滤列表。
You then just use withFilters(availableFilters)
as your filter function. 然后,您只需使用
withFilters(availableFilters)
作为过滤器函数。 You can even save that result to re-use it later. 您甚至可以保存该结果以便以后重复使用。
let filterByAvailable = withFilters(availableFilters)
let availableTaks = filteredTasks.filter(filterByAvailable)
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