按值数组过滤对象数组 es6

Question

i need a help to do a function to filter an array of object by an a array with values, example:

my array with objects:

 const persons = [ { personId: 1, name: 'Patrick', lastName: 'Smith', age: 27, allergy: [ { idAllergy: 1, name: 'Fish' },{ idAllergy: 2, name: 'Nuts' } ] }, { personId: 2, name: 'Lara', lastName: 'Blake', age: 21, allergy: [ { idAllergy: 2, name: 'Nuts' } ] }, { personId: 3, name: 'Erick', lastName: 'Robinson', age: 30, allergy: [ { idAllergy: 3, name: 'Flowers' } ] }, { personId: 4, name: 'Hilda', lastName: 'Vianne', age: 35, allergy: [ { idAllergy: 4, name: 'Chocolat' } ] } ]

my array with values to filter:

// these are idAllergy let allergy = [2,3]

so the plan is use allergy array values to seach into persons for people who has allergy to nuts and flowers and dont show them so my expected result will be:

 [{
    personId: 4,
    name: 'Hilda',
    lastName: 'Vianne',
    age: 35,
    allergy: [
    {
      idAllergy: 4,
      name: 'Chocolat'
    }
    ]
  }]

thanks in advance

Answer 1

If you want people with the allergy 2 and 3 do this:

let allergy = [2,3];
const personsWithAllergy = persons.filter(
   p => p.allergy.some(al => allergy.includes(al.idAllergy)));

 const persons = [ { personId: 1, name: 'Patrick', lastName: 'Smith', age: 27, allergy: [ { idAllergy: 1, name: 'Fish' },{ idAllergy: 2, name: 'Nuts' } ] }, { personId: 2, name: 'Lara', lastName: 'Blake', age: 21, allergy: [ { idAllergy: 2, name: 'Nuts' } ] }, { personId: 3, name: 'Erick', lastName: 'Robinson', age: 30, allergy: [ { idAllergy: 3, name: 'Flowers' } ] }, { personId: 4, name: 'Hilda', lastName: 'Vianne', age: 35, allergy: [ { idAllergy: 4, name: 'Chocolat' } ] } ] const allergy = [2,3]; const personsWithAllergy = persons.filter(p => p.allergy.some(al => allergy.includes(al.idAllergy))); console.log(personsWithAllergy);

Answer 2

const filtered = persons.filter(p => !p.allergy.some(a => allergy.includes(a.idAllergy)));

 const persons = [ { personId: 1, name: 'Patrick', lastName: 'Smith', age: 27, allergy: [ { idAllergy: 1, name: 'Fish' },{ idAllergy: 2, name: 'Nuts' } ] }, { personId: 2, name: 'Lara', lastName: 'Blake', age: 21, allergy: [ { idAllergy: 2, name: 'Nuts' } ] }, { personId: 3, name: 'Erick', lastName: 'Robinson', age: 30, allergy: [ { idAllergy: 3, name: 'Flowers' } ] }, { personId: 4, name: 'Hilda', lastName: 'Vianne', age: 35, allergy: [ { idAllergy: 4, name: 'Chocolat' } ] } ] let allergy = [2,3] const filtered = persons.filter(p => !p.allergy.some(a => allergy.includes(a.idAllergy))); console.log(filtered);

Answer 3

basically using filter and some will do the trick!

 const persons = [{ personId: 1, name: 'Patrick', lastName: 'Smith', age: 27, allergy: [{ idAllergy: 1, name: 'Fish' }, { idAllergy: 2, name: 'Nuts' }] }, { personId: 2, name: 'Lara', lastName: 'Blake', age: 21, allergy: [{ idAllergy: 2, name: 'Nuts' }] }, { personId: 3, name: 'Erick', lastName: 'Robinson', age: 30, allergy: [{ idAllergy: 3, name: 'Flowers' }] }, { personId: 4, name: 'Hilda', lastName: 'Vianne', age: 35, allergy: [{ idAllergy: 4, name: 'Chocolat' }] } ] const allergies = [2, 3] const resultWithAllergies = persons.filter(person => { const { allergy } = person; const hasAllergy = allergy.some(({ idAllergy }) => allergies.includes(idAllergy)) return hasAllergy; }) console.log(resultWithAllergies)

 const persons = [{ personId: 1, name: 'Patrick', lastName: 'Smith', age: 27, allergy: [{ idAllergy: 1, name: 'Fish' }, { idAllergy: 2, name: 'Nuts' }] }, { personId: 2, name: 'Lara', lastName: 'Blake', age: 21, allergy: [{ idAllergy: 2, name: 'Nuts' }] }, { personId: 3, name: 'Erick', lastName: 'Robinson', age: 30, allergy: [{ idAllergy: 3, name: 'Flowers' }] }, { personId: 4, name: 'Hilda', lastName: 'Vianne', age: 35, allergy: [{ idAllergy: 4, name: 'Chocolat' }] } ] const allergies = [2, 3]; const resultWithoutAllergies = persons.filter(person => { const { allergy } = person; const hasAllergy = allergy.some(({ idAllergy }) => !allergies.includes(idAllergy)) return hasAllergy; }) console.log(resultWithoutAllergies)