subprocess.check_output（）在python内部搜索文件的用法

Question

I am using subprocess.check_output() to run the basic "ls" command. From what I understand after reading documentation is that this process can help run a shell command from within the domain of python.

Let us say my example folder is home/ where I have the following files

  -rw-rw-r-- 1 aravind aravind     761 Dec  2 10:48 flux_acis_bare_479.dat
  -rw-rw-r-- 1 aravind aravind    2426 Dec  2 10:49 flux_acis_bare_481.dat
  -rw-rw-r-- 1 aravind aravind     759 Dec  2 18:46 flux_acis_hetg_479.dat
  -rw-rw-r-- 1 aravind aravind    2178 Dec  2 18:45 flux_acis_hetg_481.dat

If I do an ls search from shell for the keyword "acis", naturally all files are returned.

Now I want to do the same thing from within python.

The following is my attempt

     import os
     import subprocess

     os.chdir("home/")
     subprocess.check_output(["ls", "*acis*"])

The two " ", " " should run sequentially and I should get back all the files as a result would have been my guess. However the output I get is a file not found error.

     Command '['ls', '*acis*']' returned non-zero exit status 2

Disclaimer : I have looked at multiple Stack Overflow questions on subprocess.check_output() and tried to see if my question is a duplicate. If I have missed something please let me know.

Answer 1

As @Ry-♦ said, glob is the module you're looking for. Running glob.glob("home/*acis*") will give you a list of files and directories that match the pattern. To match recursively, like if you wanted to find a file such as home/flux_acis_folder/something_else.dat , you could use glob.glob("home/*acis**", recursive=True) .