我想将随机数从它们的列表更改为列表的最小含义

Question

I create a list of 'a' random numbers. And than I need to change odd numbers to the minimum number of this list. but it doesn't change any number, what's wrong?

import random

a = int(input('Num -> '))
s = []
for i in range(a):
    s.append(random.randint(0,10))
    if s[i]%2!=0:
        s[i]=min(s)

Answer 1

You program does, indeed, change the numbers as you requested. I added trivial print statements to track this:

import random

a = 10
s = []
for i in range(a):
    s.append(random.randint(0,10))
    if s[i]%2==0:
        print("Changing", i)
        print("\tbefore", s)
        s[i]=min(s)
        print("\t after", s)

Output:

Changing 1
    before [3, 10]
     after [3, 3]
Changing 6
    before [3, 3, 5, 9, 9, 1, 8]
     after [3, 3, 5, 9, 9, 1, 1]
Changing 7
    before [3, 3, 5, 9, 9, 1, 1, 6]
     after [3, 3, 5, 9, 9, 1, 1, 1]
Changing 8
    before [3, 3, 5, 9, 9, 1, 1, 1, 6]
     after [3, 3, 5, 9, 9, 1, 1, 1, 1]
Changing 9
    before [3, 3, 5, 9, 9, 1, 1, 1, 1, 0]
     after [3, 3, 5, 9, 9, 1, 1, 1, 1, 0]

As you can see, the even numbers do get replaced with the list minimum. Your claim that it doesn't change any number is incorrect.

If you want to change odd numbers, then you need to invert your check:

if s[i]%2 == 1:

Answer 2

changed if s[i]%2==0 to if s[i]%2!=0 to pick out the odd numbers. The first way will change even numbers

import random

a = int(input('Num -> '))

# creates your list of x random numbers
s = []
for i in range(a):
    s.append(random.randint(0,10))


# change odd numbers to the min of the original list    
for i in range(a):    
    if s[i]%2!=0:
        s[i]=min(s)

so let's say a is 10:

>>> [2, 2, 8, 1, 2, 2, 10, 7, 5, 7]

now change all odd numbers to min (in this case it's '1')

>>> [2, 2, 8, 1, 2, 2, 10, 1, 1, 1]

The answer below works too, it's just a matter of if you need it to change after each iteration of creating the list, or create the list first, and then apply your rule.