从星期几，年份和星期几获取日期

Question

I have:

• a week number
• a day of week
• a year

I want to find the date from that. How to do it in PHP?

Example:

$day = "wednesday";
$week = 1;
$year = 2019
getDate($day, $week, $year) // must return 2019-01-02

Answer 1

Try below one

$day = array(
    'Sunday',
    'Monday',
    'Tuesday',
    'Wednesday',
    'Thursday',
    'Friday',
    'Saturday'
);
$intday = array_search('Saturday', $day);
$gendate = new DateTime();
$gendate->setISODate(2019,1,$intday); //Year, week number, day
echo $gendate->format('d-m-Y');

Hope this will help you

Answer 2

Use setISODate()

$year = 2018;
$weakNum = 50;
$dayNum = 3;
$date = new DateTime();
$date->setISODate($year,$weakNum,$dayNum); 
echo $date->format('d.m.Y'); 

Answer 3

Try This :

<?php
$gendate = new DateTime();
$gendate->setISODate(2019,1,3); //year , week num , day
echo $gendate->format('Y-m-d'); //"prints"  2019-01-02

Answer 4

试试这个：

$weekNo = date("W", strtotime("2018-12-20"));