从变量中删除空格/逗号以添加到字符串

Question

I need it to look like

https://doorpasscode.kringlecastle.com/checkpass.php?i= (3333)&resourceId=77af125f-213f-4b2b-9e1e-ce156b6a838c

instead it looks like

https://doorpasscode.kringlecastle.com/checkpass.php?i= (3, 3, 3, 3)&resourceId=77af125f-213f-4b2b-9e1e-ce156b6a838c

Code:

for i in range(0, 4):
    for j in range(0, 4):
        for k in range(0, 4):
            for l in range(0, 4):
                trypass=(i,j,k,l)
                #print(i,j,k,l, sep='')
                print('https://doorpasscode.kringlecastle.com/checkpass.php?i= {}&resourceId=77af125f-213f-4b2b-9e1e-ce156b6a838c'.format(trypass).strip(','))

Answer 1

1. strip only strips from the beginning and end of the string, it doesn't strip the characters from the middle.
2. Your problem isn't really stripping, it's adding unnecessary junk in the first place by directly stringifying the tuple .

To fix both, convert trypass to a string up front with no joiner characters in the middle:

trypass = ''.join(map(str, (i,j,k,l)))

A side-note: You could shorten this a lot with itertools.product to turn four loops into one (no arrow shaped code), and avoid repeatedly stringifying by converting the range elements to str only once, directly generating trypass without the intermediate named variables:

from itertools import product

for trypass in map(''.join, product(map(str, range(0, 4)), repeat=4)):
    print('https://doorpasscode.kringlecastle.com/checkpass.php?i= ({})&resourceId=77af125f-213f-4b2b-9e1e-ce156b6a838c'.format(trypass).)

Answer 2

.format(trypass) will format the tuple as a string using the default tuple formatting rules, eg (3, 3, 3, 3) . Instead you should explicitly tell it how to format the string, like:

.format(''.join(str(i) for i in trypass))

Answer 3

You have a tuple that you want to reduce to a string.

>>> trypass = (3,3,3,3)
>>> ''.join(str(i) for i in trypass)
'3333'

Or, since you know there are exactly 4 digits,

print('https://doorpasscode.kringlecastle.com/checkpass.php?i={}{}{}{}&resourceId=77af125f-213f-4b2b-9e1e-ce156b6a838c'.format(*trypass))

Or, just iterate over the 4-digit numbers directly. itertools.product can generate the tuples for you.

import itertools
for trypass in itertools.product("0123", repeat=4):
    print('https://doorpasscode.kringlecastle.com/checkpass.php?i={}{}{}{}&resourceId=77af125f-213f-4b2b-9e1e-ce156b6a838c'.format(*trypass))