[英]Select many values as one column, not a column for each value, SQL Server
If you do this query in SQL Server it will give you 15 different columns- one for each postcode. 如果在SQL Server中执行此查询,它将为您提供15个不同的列 - 每个邮政编码一个。
SELECT
'CB89RX', 'CB259BL', 'CB19BF', 'CB245HS', 'CB30AP', 'CB12LJ',
'CB21RB', 'CB28PX', 'CB28PE', 'CB250HX', 'CB231HN', 'CB58TD',
'CB246AY', 'CB42QT', 'CB249JA' AS A
What I want is 1 column that contains all 15 values. 我想要的是包含所有15个值的1列。 How can I do this?
我怎样才能做到这一点?
You can try using UNPIVOT
您可以尝试使用
UNPIVOT
select u.postcode
from tablename
unpivot
(
postcode
for val in (CB89RX, CB259BL, CB19BF, CB245HS, CB30AP, CB12LJ, CB21RB, CB28PX, CB28PE, CB250HX, CB231HN, CB58TD, CB246AY, CB42QT, CB249JA)
) u;
You can use union : 你可以使用union:
SELECT 'CB89RX' as PostalCode
Union
Select 'CB19BF' as PostalCode
Union
Select 'CB245HS' as PostalCode
Union
...
Try this to avoid repetitive use of as . 试试这个以避免重复使用as 。
SELECT 'CB89RX' as A
union
select 'CB259BL'
union
select 'CB19BF'
union
select 'CB245HS'
union
select 'CB30AP'
union
select 'CB12LJ'
union
select 'CB21RB'
union
select 'CB28PX'
union
select 'CB28PE'
union
select 'CB250HX'
union
select 'CB231HN'
union
select 'CB58TD'
union
select 'CB246AY'
union
select 'CB42QT'
union
select 'CB249JA'
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