选择多个值作为一列，而不是每个值的列，SQL Server

Question

如果在SQL Server中执行此查询，它将为您提供15个不同的列 - 每个邮政编码一个。

SELECT 
    'CB89RX', 'CB259BL', 'CB19BF', 'CB245HS', 'CB30AP', 'CB12LJ', 
    'CB21RB', 'CB28PX', 'CB28PE', 'CB250HX', 'CB231HN', 'CB58TD', 
    'CB246AY', 'CB42QT', 'CB249JA' AS A

我想要的是包含所有15个值的1列。 我怎样才能做到这一点？

Answer 1

您可以尝试使用UNPIVOT

select u.postcode
    from tablename
    unpivot
    (
      postcode
      for val in (CB89RX, CB259BL, CB19BF, CB245HS, CB30AP, CB12LJ, CB21RB, CB28PX, CB28PE, CB250HX, CB231HN, CB58TD, CB246AY, CB42QT, CB249JA)
    ) u;

Answer 2

我想使用From .... VALUES

Select 
    val
From 
  (
  VALUES
    ('CB89RX'), 
    ('CB259BL'), 
    ....
  ) AS T (val)

sqlfiddle

Answer 3

你可以使用union：

SELECT 'CB89RX' as PostalCode
Union
Select  'CB19BF'  as PostalCode 
Union 
Select 'CB245HS' as PostalCode 
Union 
... 

Answer 4

试试这个以避免重复使用as 。

SELECT   'CB89RX'  as A
   union 
   select  'CB259BL' 
   union 
   select 'CB19BF' 
   union 
   select 'CB245HS'
   union 
   select 'CB30AP'
   union 
   select    'CB12LJ'
   union 
   select    'CB21RB'
   union 
   select    'CB28PX'   
   union 
   select    'CB28PE'
   union 
   select    'CB250HX'
   union 
   select 'CB231HN'
   union 
   select 'CB58TD'
   union 
   select 'CB246AY'
   union 
   select 'CB42QT'
   union 
   select 'CB249JA'